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finlep [7]
4 years ago
11

2H2+O2--->2H2O

Chemistry
1 answer:
Liono4ka [1.6K]4 years ago
8 0
The answer is B-2 hope this helps
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A sample of xenon gas occupies 1.90L at 251 kPa and -18°C. What was the temperature of the xenon if the gas originally measured
sertanlavr [38]

The temperature of the xenon : 180.863 K

<h3>Further explanation</h3>

Combined with Boyle's law and Gay Lussac's law  

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

P1 = initial gas pressure (N/m² or Pa)  

V1 = initial gas volume (m³)  

P2 = final gas pressure  

V2 = finalgas  volume  

T1 = initial gas temperature (K)  

T2 = final gas temperature  

P1=251 kPa

T1=-18+273=255 K

V1=1.9 L

P2=205 kPa

V2=1.65 L

\tt \dfrac{251\times 1.9}{255}=\dfrac{205\times 1.65}{T_2}\\\\T_2=\dfrac{205\times 1.65\times 255}{251\times 1.9}=180.863~K

4 0
3 years ago
The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically. The following data was obtained: t/min 0
o-na [289]

Answer:

1) The order of the reaction is of FIRST ORDER

2)   Rate constant k = 5.667 × 10 ⁻⁴

Explanation:

From the given information:

The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically.

liquid-phase reaction 2A - B signifies that the reaction is of FIRST ORDER where the rate of this reaction is directly proportional to the concentration of A.

The following data was obtained:

t/min                    0         10         20          30             40          ∞

conc B/(mol/L)    0       0.089    0.153     0.200       0.230    0.312

For  a first order reaction:

K = \dfrac{1}{t} \ In ( \dfrac{C_{\infty} - C_o}{C_{\infty} - C_t})

where :

K = proportionality  constant or the rate constant for the specific reaction rate

t = time of reaction

C_o = initial concentration at time t

C _{\infty} = final concentration at time t

C_t = concentration at time t

To start with the value of t when t = 10 mins

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 - 0}{0.312 - 0.089})

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 }{0.223})

K_1 =0.03358 \  min^{-1}

K_1 \simeq 0.034 \  min^{-1}

When t = 20

K_2= \dfrac{1}{20} \ In ( \dfrac{0.312 - 0}{0.312 - 0.153})

K_2= 0.05 \times  \ In ( 1.9623)

K_2=0.03371 \ min^{-1}

K_2 \simeq 0.034 \ min^{-1}

When t = 30

K_3= \dfrac{1}{30} \ In ( \dfrac{0.312 - 0}{0.312 - 0.200})

K_3= 0.0333 \times  \ In ( \dfrac{0.312}{0.112})

K_3= 0.0333 \times  \ 1.0245

K_3 = 0.03412 \ min^{-1}

K_3 = 0.034 \ min^{-1}

When t = 40

K_4= \dfrac{1}{40} \ In ( \dfrac{0.312 - 0}{0.312 - 0.230})

K_4=0.025 \times  \ In ( \dfrac{0.312}{0.082})

K_4=0.025 \times  \ In ( 3.8048)

K_4=0.03340 \ min^{-1}

We can see that at the different time rates, the rate constant of k_1, k_2, k_3, and k_4 all have similar constant values

As such :

Rate constant k = 0.034 min⁻¹

Converting it to seconds ; we have :

60 seconds = 1 min

∴

0.034 min⁻¹ =(0.034/60) seconds

= 5.667 × 10 ⁻⁴ seconds

Rate constant k = 5.667 × 10 ⁻⁴

4 0
3 years ago
Why do atoms receive a positive or negative charge when they give or take electrons? Include the nucleus in your
marysya [2.9K]
Atoms receive a positive charge when they take electrons. Atoms give of negative electrons.
4 0
3 years ago
Which is the formula for diarsenic pentoxide?
gladu [14]

As205

Hope this helps:)

6 0
3 years ago
Given you have 1.93 mols of NaCl, find the molarity of a 2.5 L solution
Inessa [10]

Answer:

0.77 M

Explanation:

Molarity is the concentration of a solution per liter

C= concentration

n= number of moles

V= volume of solution

The formula we will use is C= n/V

C= n/V

C= (1.93 mol NaCl)/(2.5 L of solution)

C= 0.772 mol/L

Since this concentration is given in moles per liters of a solution, this concentration is also the molarity.

C= 0.772 mol/L

*Include two significant digits in final answer*

M= 0.77 M

5 0
3 years ago
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