Answer:
CN^- is a strong field ligand
Explanation:
The complex, hexacyanoferrate II is an Fe^2+ specie. Fe^2+ is a d^6 specie. It may exist as high spin (paramagnetic) or low spin (diamagnetic) depending on the ligand. The energy of the d-orbitals become nondegenerate upon approach of a ligand. The extent of separation of the two orbitals and the energy between them is defined as the magnitude of crystal field splitting (∆o).
Ligands that cause a large crystal field splitting such as CN^- are called strong field ligands. They lead to the formation of diamagnetic species. Strong field ligands occur towards the end of the spectrochemical series of ligands.
Hence the complex, Fe(CN)6 4− is diamagnetic because the cyanide ion is a strong field ligand that causes the six d-electrons present to pair up in a low spin arrangement.
Answer:
600.7 moles
Explanation:
Applying,
PV = nRT................... Equation 1
Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.
make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 190 atm, V = 35 L, T = 135 K
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
n = (190×35)/(135×0.082)
n = 600.7 moles of xygen
Answer:
Mass = 24.36 g of N₂
Explanation:
The balance chemical equation for the decomposition of NaNO₃ is as follow;
2 NaN₃ → 2 Na + 3 N₂
Step 1: Find moles of N₂ as;
According to equation,
2 moles of NaNO₃ produces = 3 moles of N₂
So,
0.58 moles of NaNO₃ will produce = X moles of N₂
Solving for X,
X = 3 mol × 0.58 mol / 2 mol
X = 0.87 mol of N₂
Step 2: Calculate mass of N₂ as,
Mass = Moles × M.Mass
Mass = 0.87 mol × 28.01 g/mol
Mass = 24.36 g of N₂
Answer:
B
Explanation:
Hydrogen is synthesized to water by adding Oxygen.
Hydrogen is oxidised to water by combustion ( burning in presence of oxygen).
Answer:
it has 0g of sugar (hopes this helps)