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Rasek [7]
3 years ago
12

You will transform the program that was written to play a letter guessing game (project 2) to an object-oriented program.general

requirements for project 3rewrite the program from project 2 using at least one class "game", which has three member functions.all member functions will be defined asfollows:othe function prototype appears in the classdefinitionocomment describing what the function does appears directly under function prototype formal variable names are not used in any prototype the functions definition appears after themainthe first member functionis a custom constructor (to set the member variables), which receives two parameters: the first parameter is a character (the character to be guessed in that game); and the second parameter is an integer that specifies the maximum number of attempts that can be made in thegame.(the number of attempts ranges between 4 and 7 -inclusive-, this number is randomly generated in the main function using the "rand" function, you have to seed the random number generator).
Computers and Technology
1 answer:
Sedbober [7]3 years ago
6 0
We need to program from the project to even solve this.
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Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user
vlabodo [156]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

   int evekount = 0, odkount = 0;

   for(int i = 0; i<50;i++){

       cin>>numbers[i];

       if(numbers[i]%2==0){            evekount++;        }

       else{            odkount++;        }

   }

   cout<<"Even Count: "<<evekount<<endl;

   cout<<"Odd Count: "<<odkount<<endl;

   return 0;

}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

   int evekount = 0, odkount = 0;

This iterates from 1 to 50

   for(int i = 0; i<50;i++){

This gets input for the array

       cin>>numbers[i];

This checks for even

<em>        if(numbers[i]%2==0){            evekount++;        }</em>

This checks for odd

<em>        else{            odkount++;        }</em>

   }

This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

   cout<<"Odd Count: "<<odkount<<endl;

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Answer:

D. All of these

Explanation:

I hope this helps you! Have a great day!

bren~

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Explanation:

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