Ask question

Ask question

All categories

3 years ago

6

If this boat is not tied to a dock and the waves move in the same direction all day (shown by the arrow), in which direction wil

l the boat travel if left untied?

1 answer:

alex41 [277]3 years ago

6 0

Answer:

It will move up

Explanation:

I’m this bc I took the test on USA Test prep

You might be interested in

3. A sled is initially given a shove up a frictionless 23.0° incline. It reaches a maximum vertical height 1.22 m higher than wh

Delicious77 [7]

Answer:

4.88 m/s

Explanation:

Utilizing the law of conservation of energy, kinetic energy at the inclined bottom equals to the potential energy at the top hence

$0.5mv^{2}=mgh$ and making v the subject of the formula then $v=\sqrt {2gh}$ where m represnt the mass of sled, v is the initial speed, g is acceleration due to gravity and h ia the vertical height. Substituting g with 9.81 m/s2 and h with 1.22 then

$v=\sqrt{2\times 9.81\times 1.22}\approx 4.88 m/s$

6 0

4 years ago

Diamond is the one mineral in the world that cannot be scratched by any other mineral. Therefore, we refer to diamond as the ___

mart [117]

Answer:

hardest

Explanation:

Diamonds are known as the hardest naturally occurring substance known.

4 0

3 years ago

Read 2 more answers

In class we described the tidal forces that are responsible for raising and lowering thewater level near the shore of the ocean.

Sloan [31]

The newton's law of universal gravitation used to describe how a particle attracts every other particle in the universe.

The equation is given by,

$F= G\frac{m_1 m_2}{r_2}$

Where,

F= Gravitational force

$m_1, m_2 =$ masses of the objects

r= is the distance between the center of their masses

G= Gravitational constant

For our problem we have defined that,

$M_m = 7.24*10^{22}kg$ (mass of the moon)

$d= 3.84*10^8 km$ (distance Earth-moon)

G= 6.671*10^{-11}Nm^2/kg^2

M=Mass of a person

We have then,

$F_m = M\frac{6.67*10^-11*7.34*10^22}{3.84*10^8}$

$F_m = M*3.320*10^{-5} N$

In the other hand we have the force on m-mass due to earth

$F_E= MG = M*9.8N$

Ratio is given by

$\frac{F_m}{F_E} = {M*3.320*10^{-5}}{9.8} = 3.387*10^{-6}$

B) Suppose there is a group of young people surfing in the moonlight. They are directly under the moon. At this time the moon exerts its gravitational effect of the earth that causes the tide to rise. Around 6 hours later, when the earth has moved a quarter of the moon, the force on that point decreases, so the tide drops. However, after another 6 hours, people return and experience the same process. In this case the moon is not above them, but on the other side. This is because the moon having an orbit on the earth, generates an external force, similar to the previous one, but the earth reacts in the opposite way. It is like going in a car and turning it, all people will tend to get out of it, because a centrifugal force is experienced.

7 0

4 years ago

Usain Bolt's world-record 100 m sprint on August 16, 2009, has been analyzed in detail. At the start of the race, the 94.0 kg Bo

kifflom [539]

Answer:

893 Newtons

Explanation:

m = Mass of Usain Bolt = 94 kg

a = Acceleration of Usain Bolt in the first 0.89 seconds = 9.5 m/s²

From Newton's Second law

Force

$F=ma$

$\\\Rightarrow F=94\times 9.5$

$\\\Rightarrow F=893\ N$

The average horizontal force exerted by Bolt against the ground during the first 0.890 s of the race is 893 Newtons

3 0

3 years ago

Two tiny beads are 25 cm apart with no other charged objects or fields present. Bead A has a net charge of magnitude 10 nC and b

Alona [7]

Answer:

E. The force on A is exactly equal to the force on B.

Explanation:

The force between two charges is given by

$F=\dfrac{kq_1q_2}{r^2}$

where

$q_1$ = Charge on particle 1

$q_2$ = Charge on particle 2

r = Distance between the charges

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

$F=\dfrac{8.99\times 10^9\times 10\times 10^{-9}\times 1\times 10^{-9}}{(25\times 10^{-2})^2}\\\Rightarrow F=0.0000014384\ N$

This force will be exerted on both the charges equally.

So, The force on A is exactly equal to the force on B

6 0

3 years ago