All categories

2 years ago

How do u say i like u to ur crush but not make it akward

Physics

2 answers:

Sever21 [200]2 years ago

4 0

Answer:

bark at then

Explanation:

Tcecarenko [31]2 years ago

3 0

Answer:

first, become bsf with him.

then, laugh at his jokes even is it wasn't funny and make eye contact.

NEVER tell him u like him until u r 100% sure he has the slightest bit of interest towards u other than just being friends

Explanation:

You might be interested in

A cyclotron is to accelerate protons to an energy of 5.4 MeV. The superconduction electromagnet of the cyclotron produces a 2.9T

mart [117]

<h3><u>Answer;</u></h3>

Radius = 0.0818 m

Angular velocity = 2.775 × 10^7 rad/sec

<h3><u>Explanation;</u></h3>

The mass of proton m=1.6748 × 10^-27 kg;

Charge of electron e= 1.602 × 10^-19 C;

kinetic energy E= 2.7 MeV

= 2.7 × 10^6 × 1.602 × 10^-19 J;

= 4.32 × 10^-13 Joules

But; K.E =0.5m*v^2,

Hence v=√(2K.E/m)

Velocity = 2.27 × 10^7 m/s

Angular velocity, ω = v/r

Therefore; V = ωr

Hence; V = √(2K.E/m) = ωr

r= √(2E/m)/w = √E*√(2*m)/(eB)

= √E * √(2×1.6748×10^-27)/(1.602×10^-19 ×2.9)

but E = 4.32 × 10^-13 Joules

r = 0.0818 m

Angular speed

Angular velocity, ω = v/r , where r is the radius and v is the velocity

Therefore;

Angular velocity = 2.27 × 10^7 / 0.0818 m

= 2.775 × 10^7 rad /sec

3 0

3 years ago

How long do comets last?

Hoochie [10]

I don't believe their is a legitimate answer for this question..

8 0

3 years ago

A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi

krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

(m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

k = [(m)×(v^2)]/(x^2)

k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

v^2 = [(k)(x^2)]/m

v = \sqrt{ [(k)(x^2)]/m}

v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

= 0.491 m/s

8 0

3 years ago

Read 2 more answers

Choose all that apply. Which of the following questions could you answer by measuring length? 1 How tall are you? 2How far is it

horsena [70]

The correct options are:

1 How tall are you?

2How far is it from your house to your school?

3How wide is your refrigerator?

All these measurements involve to measure a length. Instead, the other two options involve to measure different physical quantities; for instance, the question

4 How much does your sister weigh?

Involve to measure a weight (and so, a mass), while the question

5 How warm is it in San Diego?

requires to measure a temperature.

8 0

3 years ago

The electric field 14.0 cm from the surface of a copper ball of radius 2.0 cm is directed toward the ball's center and has magni

Marina CMI [18]

Answer:

Q = - 256 X 10⁻⁷ C .

Explanation:

Electric field due to a charge Q at a distance d from the center is given by the expression

E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹

Put the given value in the equation

9 x 10² = $\frac{9\times10^9\times Q}{(14+2)^2\times10^{-4}}$

Q = $\frac{9\times16^2\times10^{-2}}{9\times10^9}$

Q = - 256 X 10⁻⁷ C .

It will be negative in nature as the field is directed towards the center.

5 0

3 years ago