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Vikki [24]
3 years ago
14

Two tiny beads are 25 cm apart with no other charged objects or fields present. Bead A has a net charge of magnitude 10 nC and b

ead B has a net charge of magnitude 1 nC. Which one of the following statements is true about the magnitudes of the electric forces on these beads?A. The force on A is 100 times the force on B.B. The force on B is 10 times the force on A.C. The force on B is 100 times the force on A.D. The force on A is 10 times the force on B.E. The force on A is exactly equal to the force on B.
Physics
1 answer:
Alona [7]3 years ago
6 0

Answer:

E. The force on A is exactly equal to the force on B.

Explanation:

The force between two charges is given by

F=\dfrac{kq_1q_2}{r^2}

where

q_1 = Charge on particle 1

q_2 = Charge on particle 2

r = Distance between the charges

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

F=\dfrac{8.99\times 10^9\times 10\times 10^{-9}\times 1\times 10^{-9}}{(25\times 10^{-2})^2}\\\Rightarrow F=0.0000014384\ N

This force will be exerted on both the charges equally.

So, The force on A is exactly equal to the force on B

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An object is thrown upward with some velocity. If the object rises 77.5 m above the point of release, (a) how fast was the objec
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Answer:

v_o=39\ m/s\\t_m=4\ s

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=H+\frac{v_o^2}{2g}

The object referred to in the question is thrown from a height H=0 and the maximum height is hm=77.5 m.

(a)

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\displaystyle v_o=\sqrt{2gh_m}

v_o=\sqrt{2\cdot 9.8\cdot 77.5}

v_o=39\ m/s

(b)

The maximum time or the time taken by the object to reach its highest  point is calculated as follows:

\displaystyle t_m=\frac{v_o}{g}

\displaystyle t_m=\frac{39}{9.8}

t_m=4\ s

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