Question

3. A sled is initially given a shove up a frictionless 23.0° incline. It reaches a maximum vertical height 1.22 m higher than where it started at the bottom. What was its initial speed?

Answer 1

Answer:

4.88 m/s

Explanation:

Utilizing the law of conservation of energy, kinetic energy at the inclined bottom equals to the potential energy at the top hence

$0.5mv^{2}=mgh$ and making v the subject of the formula then $v=\sqrt {2gh}$ where m represnt the mass of sled, v is the initial speed, g is acceleration due to gravity and h ia the vertical height. Substituting g with 9.81 m/s2 and h with 1.22 then

$v=\sqrt{2\times 9.81\times 1.22}\approx 4.88 m/s$