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Step2247 [10]
3 years ago
5

Usain Bolt's world-record 100 m sprint on August 16, 2009, has been analyzed in detail. At the start of the race, the 94.0 kg Bo

lt accelerated from rest at a rate of 9.50 m/s2 for the first 0.890 s, and eventually reached a top speed of 12.4 m/s by exerting an average horizontal force of 820 N against the ground for the entire 9.58 s duration of the race.What was the average horizontal force (in N) exerted by Bolt against the ground during the first 0.890 s of the race?
Physics
1 answer:
kifflom [539]3 years ago
3 0

Answer:

893 Newtons

Explanation:

m = Mass of Usain Bolt = 94 kg

a = Acceleration of Usain Bolt in the first 0.89 seconds = 9.5 m/s²

From Newton's Second law

Force

F=ma

\\\Rightarrow F=94\times 9.5

\\\Rightarrow F=893\ N

The average horizontal force exerted by Bolt against the ground during the first 0.890 s of the race is 893 Newtons

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A spring with constant 185 N/m is compressed 1.38 m with a mass of 0.53 kg. How fast is it going 2.5 m above the ground?
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The velocity 2.5 m above the ground will be 49.07 m/sec.

<h3>What is spring force?</h3>

The force required to extend or compress a spring by some distance scales linearly concerning that distance is known as the spring force. Its formula is;

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The formula for force is;

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Equating both the equation;

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a=kx/m

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a  = 481.6 m/s²

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v²=u²+2as

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v = 49.07 m/sec

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To learn more about the spring force refer to the link;

brainly.com/question/4291098

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