In this puzzle, each letter represents a different digit. What does the O represent? What does M?

The two dice are rolled. what is the theoretical chance that they land to form a sum of 11?

Rufina [12.5K]

Answer:

Propability of getting either sum is 2/9

Step-by-step explanation:

Well, we know that there are 36 total arrangements of the two six sided die. So we have a possibility of 3,4 and 4,3. Likewise, we have a possibility of 5,2 and 2,5. We also have a possibility of 1,6 and 6,1. That takes care of the probability That you get two die that add up to 7. Now for 11, you have 5,6 and 6,5. So since you asked for the probability of getting either or, you add all the probabilities, which is 6/36+2/36=8/36=2/9. So the probability of getting either sum is 2/9.

5 0

3 years ago

2. A student had taken six tests and received scores of 88, 73, 81, 83, 79, 94. The seventh test

Veronika [31]

Answer:

a) 83

b) mean and mode are both 83

Step-by-step explanation:

a) mean is the average. so add all the numbers and divide by the number of numbers.

<u>88 + 73 + 81 + 83 + 79 + 94 + T</u> = 83

7

b) median - put the numbers in numerical order, smallest to largest, what is the middle number (4th number) 73, 79, 81, 83, 83, 88, 94

mode - which number shows up most frequently?

8 0

4 years ago

The polynomial equation x^4 + x^3 + x^2 + x + 1 = 0 has zero positive real roots. Please select the best answer from the choices

const2013 [10]

There are zero positive real roots for the given polynomial equation $x^4 + x^3 + x^2 + x + 1 = 0$ . This is explained by Descarte's rule of signs. So, the best choice is T (true).

<h3>What is Descarte's rule of signs?</h3>

Descarte's rule of signs tells about the number of positive real roots and negative real roots.
The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.

<h3>Calculation:</h3>

The given polynomial equation is $x^4 + x^3 + x^2 + x + 1 = 0$

On applying Descarte's rule of signs,

$f(x)=x^4 + x^3 + x^2 + x + 1$

Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.

$f(-x)=(-x)^4+(-x)^3+(-x)^2+(-x)+1\\ = x^4-x^3+x^2-x+1$

Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.

Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).

Learn more about Descarte's rule of signs here:

brainly.com/question/11590228

#SPJ1

5 0

2 years ago

A line goes through the points (-6, -8) and (12, 7). a) What is the slope of the line? Show your work. b) Write the equation of

kompoz [17]

m = $\frac{5}{6}$ , y - 7 = $\frac{5}{6}$ ( x - 12), y = $\frac{5}{6}$ x - 3