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2 years ago

Solve for x I don't know what to do with the parenthesis

Mathematics

1 answer:

irinina [24]2 years ago

6 0

Answer:

x=21

Step-by-step explanation:

Notice the right angle. Perpendicular to it on the right, we have two complementary angles, 25, and 3x+2 (you can ignore the parentheses basically). Because they are complementary angles, they will add up to 90, so we can make an equation to solve for x:

25+3x+2=90

3x+2=65

3x=63

x=21

So x=21 is the correct answer. Let me know if you have any questions about my explanation.

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PLEASE HELP WITH GEOMETRY!!!

svetoff [14.1K]

Answer:

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Step-by-step explanation:

7 0

2 years ago

Can someone help answer this

kolezko [41]

Answer:

v = 55

Step-by-step explanation:

Plug in the values provided into the equation

v = u + at

v = 23 + 8 * 4

Solve

v = 23 + 8 * 4

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6 0

2 years ago

Read 2 more answers

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

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2 years ago

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FrozenT [24]

Number one: Just plot down on the number like the numbers you have. Just took the test for this.

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2 years ago

Whitney kicks a football off the ground. The height, h , in feet, of the football above the ground after t seconds is given by h

malfutka [58]

Answer:

after 4seconds

Step-by-step explanation:

Given the height, h , in feet, of the football above the ground after t seconds expressed by h ( t ) = − 8 t^2 + 32 t, the height of the ball on the ground is 0feet.

Substitute h(t) = 0 into the expression and calculate t;

h ( t ) = − 8 t^2 + 32 t

0 = − 8 t^2 + 32 t

8t² = 32t

8t = 32

Divide both sides by 8

8t/8 = 32/8

t = 4s

Hence the football hits the ground after 4seconds

5 0

2 years ago