Centroid, orthocenter, circumcenter, and incenter are the four locations that commonly concur.
<h3>Explain about the concurrency of medians?</h3>
A segment whose ends are the triangle's vertex and the middle of the other side is called a median of a triangle. A triangle's three medians are parallel to one another. The centroid, also known as the point of concurrency, is always located inside the triangle.
The incenter of a triangle is the location where the three angle bisectors meet. The only point that can be inscribed into the triangle is the center of the circle, which is thus equally distant from each of the triangle's three sides.
Draw the medians BE, CF, and their intersection at point G in the triangle ABC. Create a line from points A through G that crosses BC at point D. We must demonstrate that AD is a median and that medians are contemporaneous at G since AD bisects BC (the centroid)
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Answer: x - 3y = -2
x = -2 + 3y
x - 3y = 16
x = 16 + 3y
Answer:
The point is at about (4.5, 100).
Step-by-step explanation:
Minka's line is p = 22t, which has a y-intercept of 0.
Kenji's line is p = 50 + 11t, which has a y-intercept of 50.
Find the line with y-intercept at 0 and the line with y-intercept at 50. Follow the two lines until they intersect. The point of intersection is about (4.5, 100).
You can find this point by setting the two equations equal to each other:
22t = 50 + 11t
Subtract 11t from both sides.
11t = 50
t = 50/11 ≈ 4.545
Then you can find the p value for this point by plugging t = 4.545 into either equation.
p = 22(4.545) = 99.99
p = 50 + 11(4.545) = 99.995
On the graph the point is about (4.5, 100).
Answer:
A: 105.6 B: 26.40
Step-by-step explanation:
if you divide 132 by 5, you get Meteorite B, 26.40, then minus that from 132, and you get Meteorite A, 105.6.
To check, do 26.40x5 and you should get 132.