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3 years ago

explain why in a drawer only containing two different colors of socks one must pull 3 out to find a matching pair?

1 answer:

8 0

If there are only two colors (let's say blue and red), here's what can happen:
sock #1 is blue
#2 is either blue or red. If blue, it matches #1 and you have a pair.
if red, go to #3
#3-either blue or red. If blue, matches #1. If red, matches #2.

OR sock #1 is red... then just reverse the colors. Basically, if you have three things that can only be in two groups, then even if two of them are different, the last one has to match one of them.

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Need help with a system of equations

sweet [91]

Answer:

$\boxed{x - y = -2\sqrt{7}}$

Given:

$x + y = 4 \\ \\ {x}^{2} + {y}^{2} = 22 \\ \\ {x}^{4} = {y}^{4} - 176 \sqrt{7}$

Step-by-step explanation:

$= > {x}^{4} = {y}^{4} - 176 \sqrt{7} \\ \\ = > {x}^{4} - {y}^{4} = - 176 \sqrt{7} \\ \\ = > {( {x}^{2}) }^{2} - { ({y}^{2}) }^{2} = - 176 \sqrt{7} \\ \\ = > ( {x}^{2} + {y}^{2} )( {x}^{2} - {y}^{2} ) = - 176 \sqrt{7} \\ \\ = > ( {x}^{2} + {y}^{2}) (x + y)(x - y) = - 176 \sqrt{?} \\ \\ = > 22 \times 4(x - y) = - 176 \sqrt{7} \\ \\ = > 88(x - y) = - 176 \sqrt{7} \\ \\ = > x - y = - \frac{176 \sqrt{7} }{88} \\ \\ = > x - y = - 2 \sqrt{7}$

Identity used:

${x}^{2} - {y}^{2} = (x + y)(x - y)$

7 0

3 years ago

Read 2 more answers

What is the value of the expression below? 32^3/5 O A. 6/5 B. 6 O c. 96/5 O D. 8

Hoochie [10]

Answer:

D. 8

Step-by-step explanation:

32^(3/5) is the same as $\sqrt[5]{32}$ ^3.

$\sqrt[5]{32}$ = 2 because 2^5=32

2^3 = 8

6 0

2 years ago

Read 2 more answers

6(2x-1) over 5. I need help so help me pleeease

pav-90 [236]

Answer:

(12x - 6)/5

Step-by-step explanation:

6(2x-1)/5 => (12x - 6)/5 because of the distributive property.

You cannot simplify farther after you reach (12x - 6)/5.

3 0

3 years ago

Can someone please help

mario62 [17]

The answer is B) Translation, Congruent

6 0

3 years ago

The graph represents a person's heart rate in beats per minute during 30 minutes of exercise.

Andrej [43]

Looking at the graph closely we can see that the heart rate increases from 0 to 6 min then became steady from 6 to 25 min then finally decreases from 25 to 30 min. Therefore the correct answer is:

“The heart rate increases for 6 minutes, remains constant for 19 minutes, and then gradually decreases for 5 minutes.”

In real life cardiac exercises, we can interpret that the period from 0 to 6 min is the period where the person is still warming up thus leading to an increase in heart rate. At 6 min, the person is fully warmed up hence reaching a stable heart rate. Then at 25 min, the person starts cooling down which means that the exercise is ending soon.

5 0

3 years ago