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dusya [7]
3 years ago
12

Which relation is a function?

Mathematics
2 answers:
Inessa [10]3 years ago
6 0
To be a function, a graphed equation must pass the vertical line test, i.e. a vertical line must not pass through more than one point on the graph, or the equation must not have more than one y-value for each x-value. All but the lower-left graph fail this test, and are therefore not functions. 
Serjik [45]3 years ago
4 0
The answer is the parabola so the one that literally looks like a "U".
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William wants to buy a new skateboard that costs $48.80. He has saved ¼ of the amount necessary. How much money has he saved?
vesna_86 [32]

Answer:

He saved 12.2 dollars

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What binomial must he added to (3r+14) to make the sum of the two polynomials equal (8r-6)
rodikova [14]

Answer:

(5r - 20)

Step-by-step explanation:

(3r + 14) + (Ar + B) = (8r - 6)

B = -6 - 14 = -20

A = 8 - 3 = 5

4 0
3 years ago
Any help on this pleasee anyone??
meriva
False, it would not make a right triangle
8 0
3 years ago
Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
3 years ago
Priya has a recipe for banana bread. She uses 7 ½ cups of flour to make 3 loaves of banana bread. Andre will follow the same rec
Mnenie [13.5K]

Answer:

Option B)

b = \dfrac{2}{5}f  

Step-by-step explanation:

We are given the following in the question:

Priya uses 7\frac{1}{2} cups of flour to make 3 loaves of banana bread.

Thus, we can write the ration of bread to  amount of flour used as:

\text{Ratio} = \dfrac{3}{7\frac{1}{2}} = \dfrac{3}{\frac{15}{2}} = \dfrac{6}{15}

Now, b loaves of banana bread using f cups of flour.

This measurement will follow the same ratio.

Thus, we can write:

\dfrac{b}{f} = \dfrac{6}{15}\\\\b = \dfrac{2}{5}f

Thus, the correct answer is

Option B)

b = \dfrac{2}{5}f

4 0
3 years ago
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