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4 years ago

Which relation is a function?

Mathematics

2 answers:

Inessa [10]4 years ago

6 0

To be a function, a graphed equation must pass the vertical line test, i.e. a vertical line must not pass through more than one point on the graph, or the equation must not have more than one y-value for each x-value. All but the lower-left graph fail this test, and are therefore not functions.

Serjik [45]4 years ago

4 0

The answer is the parabola so the one that literally looks like a "U".

You might be interested in

F(x)=x²+4x-7 determine the vertex

asambeis [7]

Answer:

The vertex of this parabola is $(-2,-11)$

Step-by-step explanation:

One way of finding the x-coordinate of the vertex of a parabola is by using the equation $-\frac{b}{2a}$

From the function $f(x)=x^2+4x-7$ , we can see that

$a=1\\b=4\\c=-7$

This means that

$-\frac{b}{2a}=-\frac{4}{2(1)} =-2$

So, the x-value of the vertex is -2. Now, we can plug this x-value into the function to find the y-coordinate of the point.

$f(x)=x^2+4x-7\\\\f(-2)=(-2)^2+4(-2)-7\\\\f(-2)= 4-8-7\\\\f(-2)=-11$

Thus, the vertex of this parabola is $(-2,-11)$

3 0

3 years ago

Which polynomial is a perfect square trinomial? (4 points) 9x2 − 12x + 4 36b2 − 24b + 16 16x2 − 24x − 9 4a2 − 10a − 25

loris [4]

I believe it's 9x2-12x+4 but I'm not quite sure cause we haven't yet gone over this in class.

My friend also believes it is this (she's in a higher level math grade than me). I'm so sorry this isn't more helpful.

5 0

3 years ago

Read 2 more answers

What are the next two terms in the sequence 1, 8, 27, 64..., written as coordinate pairs (n,

zhuklara [117]

Answer:

C)(5, 125), (6, 216)

Step-by-step explanation:

Well firstly, there's no actual way to know. There could be anything there, as for any n pairs (x, y) with distinct x-s, there exists a (n-1 or less)-degree polynomial that models them perfectly, and infinitely many polynomials of degree n (or more).

If we input those terms to a polynomial interpolator, we'll get an answer every time.

With this one, it will be the right answer though!

But to be serious, let's find out what the numbers are. We can notice they're all cubic numbers.

There's 1, which is 1^3, then theres 2^3, then it's 3^3, then 4^3.

It's reasonable to expect that we are expected to assume (x, x^3) is the rule.

We can see that the answer C (5, 5^3), (6, 6^3) fits this narrative.

6 0

3 years ago

Pls help me i need help asap as possible

TiliK225 [7]

The first one is A and the second one is D.

6 0

3 years ago

1. 112 2. 136 3. 68 4. 158 5. 129

RideAnS [48]

Answer:

4. 158

Step-by-step explanation:

First let's make things a little simpler and put these arcs in terms of x. We know that the degree measure around the outside of a circle, regardless of its size, is 360. So let's say that arc BC is x. That means that arc BDC is 360 - x. This is because arc BC + arc BDC = 360. Substituting in our x's we have:

x + 360 - x = 360 and

360 = 360. (That's just the proof that putting in our x's as we did does in fact work!)

Following the formula then, we have

$22=\frac{1}{2}(360-x-x)$ and

$22=\frac{1}{2}(360-2x)$

Multiply both sides by 2 to get rid of the fraction and get

44 = 360 - 2x

Subtract 360 rom both sides to get

-316 = -2x

Divide both sides by -2 to get that x = 158

Since we are looking for arc BC and we designated arc BC as our x, that means that arc BC = 158.

3 0

4 years ago