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scoundrel [369]

3 years ago

14

the jones family wants to enclose their circular garden with a fence. to the nearest foot , what is the minimum length of fencin

g they need to buy

1 answer:

Elena L [17]3 years ago

7 0

Answer:

The answer is D. 393ft

Step-by-step explanation:

So if you do 62.5•2=125

Then you do 125•3.14=392.5

After that then you round 392.5 and you get 393

theres your answer.

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Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

3 years ago

Given: -1/2x > 6.<br><br>Choose the solution set.

elena55 [62]

Answer:

x <-12

Step-by-step explanation:

-1/2x > 6

Multiply each side by-2. This will flip the inequality

-2 *-1/2x < 6*-2

x <-12

8 0

3 years ago

There are 221 students on a field trip.

Liula [17]

Answer:

The answer is 31

Step-by-step explanation:

221 divided by 6 is 36-5=31

This is correct because if you divide 221 by 6 you get 36 the subtract 5 from 36 and get 31. To check this answer just do 31+5=36 times 6 which is 216 and 221 minus 5 is 216:)

8 0

3 years ago

41>6m-7 help please

oksian1 [2.3K]

41> 6m-7.
So, I added 7 to both sides and got 48>6m and then divided both sides by 6 to get 8>m or m<8.

3 0

3 years ago

How to determine whether to move right or left on the number line when adding rational numbers?

Vedmedyk [2.9K]

So if you're adding two negatives you move left, positive you move right, and when you have to determine a negative, and a positive you just have to see which one is the farthest from zero which the farthest one's sign is either positive, or negative. Positive to move right, and negative to move left.

7 0

3 years ago