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Zarrin [17]
3 years ago
6

If one penny, two dimes, and one quarter are added to the bag, what is the new probability that Marissa will draw a nickel? Writ

e your answer as a fraction, as a decimal, and as a percent. 25% chance. (I gave all info please answer this:
In which situation is it more likely that Marissa will draw a nickel
Mathematics
2 answers:
anastassius [24]3 years ago
8 0

Answer:

As a fraction it's ¼, as a decimal it's 0.25 and as a percentage it's 25%

gladu [14]3 years ago
7 0

Answer:

= 1/5

.2

20%

Step-by-step explanation:

In the bag there are 5 pennies, 4 nickels , 5 dimes, 2 quarters

We add 1 penny 2 dimes and 1 quarter

Now in the bag

6 pennies, 4 nickels, 7 dimes, 3 quarters

for a total of 20 coins

P ( nickel) = number of nickels / total

                 = 4/20 = 1/5

                  .2

                   20%

She is more likely to draw a nickel before the 1 penny 2 dimes and 1 quarter because there are fewer coins in the bag that are not nickels

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It is 6 inches if you have 8 3/4 segments lined up togehter


5 0
4 years ago
What math property is 8 times 1/8
Dmitry [639]

Answer:

i think it is the multiplicative identiy property

Step-by-step explanation:

5 0
3 years ago
Solve the following equation: 2(4^2 + 10) =
lesantik [10]

Answer:

52

Step-by-step explanation:

2(4^2 + 10) =

We do what's in the parenthesis first.

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3 0
4 years ago
Read 2 more answers
Lập bảng biến thiên và tìm tập giá trị của y=2x-4
Nikitich [7]
The answer is -8 (-8=2*-4)
7 0
3 years ago
When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
aleksandr82 [10.1K]

Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

x^2-(3x+528)

The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

But we know that x is positive, so we only accept the solution x = 27

6 0
3 years ago
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