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Alexxandr [17]
3 years ago
6

A tree measured 18 1/2 feet tall. over the next 7 1/2 years grew to be 63 1/2 feet tall.During the 7 1/2 years,what was the aver

age yearly growth rate of tree?
Pls help me
Mathematics
2 answers:
zhuklara [117]3 years ago
7 0

Answer:

It would be 6.5

Step-by-step explanation:

mixer [17]3 years ago
6 0

Answer:

6.5

Step-by-step explanation:

First subtract how tall it was 7 1/2 years ago from how tall it is now.

63 1/2 - 18 1/2 =

63 1/2 -  18 1/2 =  45

So in the 7 1/2 years the tree grew 45 feet. To get the average yearly growth for the 7 1/2 year period you have to divide the 45 feet by 7 1/2 years. = 6

It makes it much easier if you change the fractions to decimals.

63 1/2 = 63.5

7 1/2 = 7.5

63.5  ÷  7.5  = 8.46(repeated)7 feet per year so 6.500 rounded

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Option c

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A system of equations are given to us. And we need to solve them . The given system is

\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

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Thefore the required answer is ,

\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}

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