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4 years ago

11

Any factor that can change

1 answer:

densk [106]4 years ago

5 0

The things that change in an experiment are called variables. A variable is any factor, trait, or condition that can exist in differing amounts or types. An experiment usually has three kinds of variables: independent, dependent, and controlled.

a factor which can be changed in a experiment. ... all factors which remain the same for each repeated trial for all levels of the independent variable

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"I haven't missed a day of work in the past year, and I'm committed to this company, so I determined that a 20 percent salary in

ohaa [14]

Answer: a. I made comparisons with others' salaries."

Explanation:

Equity theory simply refers to the principle that the actions of individuals are based on fairness and in a situation whereby there's no fairness or equity, the workers will seek to address such differences.

According to the equity theory, workers believe that everyone who puts in a similar input should get a similar reward. Therefore, in this case since Ted used the equity theory, he'll make a comparison with the salary of others.

7 0

3 years ago

Diogo has a utility function,U(q1, q2) = q1 0.8 q2 0.2,where q1 is chocolate candy and q2 is slices of pie. If the price of slic

guapka [62]

Answer:

$(0.5 \times 8q_2)+q_2=100\\\\5q_2=100\\\\q_2=20$

since $q_2 = 20$

$q_1 = 8*20\\\\q_1=160$

Explanation:

U(q₁ q₂)

$q_1^{0.8}q_2^{0.2}\\\\P_1= \$0.5 \ P_2=\$1 \ Y=100$

Budget law can be given by

$P_1q_1+P_2q_2=Y\\\\0.5q_1+q_2=100$

Lagrangian function can be given by

$L=q_1^{0.8}q_2^{0.2}+ \lambda (100-0.5q_1-q_2)$

First order condition csn be given by

$\frac{dL}{dq} =0.8q_1^{-0.2}q_2^{0.2}-0.5 \lambda=0\\\\0.5 \lambda=0.8q_1^{-0.2}q_2^{0.2}---(i)$

$\frac{dL}{dq} =0.2q_1^{0.8}q_2^{-0.8}- \lambda=0\\\\ \lambda=0.2q_1^{0.8}q_2^{-0.8}---(ii)$

$\frac{dL}{d \lambda} =100-0.5q_1-q_2=0\\\\0.5q_1+q_2=100---(iii)$

From eqn (i) and eqn (ii) we have

$\frac{0.5 \lambda}{\lambda} =\frac{0.8q_1^{-0.2}q_2^{0.2}}{0.2q_1^{0.8}q_2^{-0.8}} \\\\0.5=\frac{4q_2}{q_1}\\\\q_1=8q_2}$

Putting $q_1=8q_2$ in euqtion (iii) we have

$(0.5 \times 8q_2)+q_2=100\\\\5q_2=100\\\\q_2=20$

since $q_2 = 20$

$q_1 = 8*20\\\\q_1=160$

3 0

3 years ago

Financial statement data for the years 20Y5 and 20Y6 for Black Bull Inc. follow:

const2013 [10]

Answer and Explanation:

a. The computation of the earning per share is given below:

As we know that

Earning per share = (Net income - preference dividend) ÷ (average no of common shares oustanding)

For 20Y5

= ($1,508,000 - $60,000) ÷ 80,000 shares

= $18.1

For 20Y6

= ($2,676,000 - $60,000) ÷ 120,000 shares

= $21.8

b. Since the earning per share is increased from 20Y5 to 20Y6 so it is favorable

4 0

3 years ago

A Person who works and provides services for a fee, but not a full time employee. . A. Vendor . . B. Broker . . C. Contractor .

Sveta_85 [38]

The answer: C. Contractor

6 0

3 years ago

Read 2 more answers

When Jason filled out his application his statements had to be ______________ to be considered legal.

Verizon [17]

Answer:

Representations

Explanation:

When Jason filled out his application his statements had to be representations to be considered legal.

To fill application and to represent application it must be considered legal.

5 0

3 years ago