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Digiron [165]
3 years ago
8

Help I don’t get these

Mathematics
1 answer:
Bad White [126]3 years ago
6 0

Answer:

The first one is not a funtion

Step-by-step explanation:

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Given the function f(x)=-5x^2+2x+9,find f(1) and f(2) Choose the statement that is true concerning these two values
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F(1) = -5(1)^2+2(1)+9 = 6
f(2) = -5(2)^2+2(2)+9 = -9

So, because f(1) = 6 is positive and f(2) = -9 is negative, f(1) > f(2).

f(1) is greater than f(2)!
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Throught the year Janet took 4 math test; her average score was 90. If she scored a 95,90 and 85 on the first three tests, what
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3 years ago
In the past year Jenny watched 44 movies that she thought were very good. She watched 55 movies over the whole year. Of the movi
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To solve this problem, we must divide the number of movies that Jenny thought were very good by the total number of movies she watched. This is because we are finding a percentage, which represents a part out of a whole that have a factor, which in this case is very good movies. First, we begin by dividing 44/55. Then, we realize that both the numerator and the denominator are divisible by 11, so if we divided them both by 11 that would simplify the fraction.

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Next, we can now easily divide our simplified fraction.

4/5 = 0.8

Finally, we must multiply by 100, because a percentage is a portion of 100 (the total is 100%). This is equivalent to moving the decimal point two places to the right.

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7 0
3 years ago
I am so lost, please help
skelet666 [1.2K]

Answer:

u=\frac{9}{t}-\frac{1}{2} a t

Step-by-step explanation:

Step 1: Given equation: 9=\frac{1}{2} a t^{2}+u t

To get u, by subtraction equality property subtract both sides of the equation by  \frac{1}{2} a t^{2}.

\Rightarrow 9-\frac{1}{2} a t^{2}=\frac{1}{2} a t^{2}+u t-\frac{1}{2} a t^{2}  

\Rightarrow 9-\frac{1}{2} a t^{2}=u t  

Step 2: By division equality property, divide both sides of the equation by t.

\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}

$\Rightarrow \frac{9}{t}-\frac{1}{2} a t=u$  

Therefore, $u=\frac{9}{t}-\frac{1}{2} a t$.

So, in Emily’s physics class, she got $u=\frac{9}{t}-\frac{1}{2} a t$.

7 0
3 years ago
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