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jonny [76]
3 years ago
11

(x 2 + 4x + 8)(2x - 1) find the product

Mathematics
1 answer:
liberstina [14]3 years ago
6 0

the correct answer to the problem you are facing should be 24x

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The $414 price charges a store for a small refrigerator consists of the refrigerator's original cost to the store plus a profit
navik [9.2K]

Answer:

<h2>$351.9</h2>

Step-by-step explanation:

the question is not formatted well

<em>A store charges $414 for a small refrigerator, the price consists of the refrigerator's original cost to the store plus a profit 15% what was the refrigerator's original cost to the store?</em>

Step one:

given data

we are told that the price of the small refrigerator contains both the original price and 15% profit

mathematically

$414= original price + 15% profit

Step two:

let us solve for 15% of 414

=(15/100)*414

=0.15*414

=$62.1

This shows that the profit is $62.1

let the original price be x

$414= x + 62.1

solve for x

x=414-62.1

x=351.9

<u>The refrigerator's original cost to the store $351.9</u>

4 0
3 years ago
Find the average. Round your answer to the nearest whole number.<br><br> 8, 12, 7, 5, 2
AVprozaik [17]

Answer:

7

Step-by-step explanation:

8 + 12 + 7 + 5 + 2= 34

34/5 =6.8

Rounded =7

5 0
3 years ago
There are four more women than men at a golf club.
marissa [1.9K]

Answer: I think its 4 + 2m

5 0
3 years ago
Anyone know the answers for #8 and #9?
babymother [125]
Check the picture below, notice those three quadrilaterals.

the square, is really a rectangle and is also a rhombus, but with right-angles and equal sides.

8 0
3 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
1 year ago
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