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VladimirAG [237]
3 years ago
9

What is the possible formula of a compound formed when sodium and chlorine bond

Chemistry
1 answer:
Karolina [17]3 years ago
5 0
NaCl, when you combine sodium and chlorine
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The barium isotope 133ba has a half-life of 10.5 years. a sample begins with 1.1×1010 133ba atoms. how many are left after (a) 5
Sladkaya [172]
<span>a) 7.9x10^9 b) 1.5x10^9 c) 3.9x10^4 To determine what percentage of an isotope remains after a given length of time, you can use the formula p = 2^(-x) where p = percentage remaining x = number of half lives expired. The number of half lives expired is simply x = t/h where x = number of half lives expired t = time spent h = length of half life. So the overall formula becomes p = 2^(-t/h) And since we're starting with 1.1x10^10 atoms, we can simply multiply that by the percentage. So, the answers rounding to 2 significant figures are: a) 1.1x10^10 * 2^(-5/10.5) = 1.1x10^10 * 0.718873349 = 7.9x10^9 b) 1.1x10^10 * 2^(-30/10.5) = 1.1x10^10 * 0.138011189 = 1.5x10^9 c) 1.1x10^10 * 2^(-190/10.5) = 1.1x10^10 * 3.57101x10^-6 = 3.9x10^4</span>
4 0
3 years ago
Read 2 more answers
What is the major defining property of gasses?.
jonny [76]

Answer:

Gases have no definite shape or volume. They are fluid, allowing particles/molecules to move freely.

The behavior of a gas is that the volume changes directly with temperature. With a constant volume, the pressure will be directly proportional to the amount of gas.

Explanation:

These are some of the properties I can think of

5 0
2 years ago
The substances sodium (Na), oxygen (O2), and sodium oxide (Na20) participate in this chemical reaction
Margaret [11]

Answer:

C

Explanation:

This is a synthesis or a combination reaction , which involves the oxygen combining with sodium to make one compound.

hope it helps.

you're welcome.

8 0
3 years ago
A prototype is usually different from the final product
Assoli18 [71]
True. The prototype is usually the "rough draft" the figure out what needs fixed or upgraded before they make the final product "final draft". Hope that helped!
7 0
3 years ago
When 0.513 g of biphenyl (c12h10 undergoes combustion in a bomb calorimeter, the temperature rises from 26.3 ?c to 29.7 ?c?
olasank [31]
When 0.514 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.8 C to 29.4 C. Find ⌂E rxn for the combustion of biphenyl in kJ/mol biphenyl. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.86 kJ/ C. 



<span>The answer is - 6.30 * 10^3 kJ/mol 

</span>
3 0
3 years ago
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