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Sloan [31]
3 years ago
12

in the ambrose family the ages of the three children are three consecutive even integers . if the age of the youngest child is r

epresented by x + 3 write an eaqation to represent the oldest child.if the sum of the ages is 42 write an equation and solve for x. how old is the oldest child
Mathematics
1 answer:
klemol [59]3 years ago
3 0

The ages are consecutive even numbers.
The youngest child is  (x+3) years old.
Every even number is 2 more than the one before it.
So the three ages are

           (x + 3),  (x + 5),  and  (x + 7).

Their sum is    x+3  +  x+5  +  x+7  =  3x + 15

But we're told that their sum is  42, so we can write

                                              3x + 15 = 42  <== the equation

Subtract 15 from each side:  3x         =  27

Divide each side by  3 :          x         =   9    <== the solution

So the three ages are  12,  14,  and  16.

The oldest child is  16  years old.

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6 0
3 years ago
Figure 3<br> 2n + 10<br> 140<br> 4n -40<br> 80<br> 2n<br> 3n - 20<br> I need help
abruzzese [7]

Answer:

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3 0
2 years ago
Solve the equation 3.5z-2.7z=-6
zysi [14]
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5 0
3 years ago
Read 2 more answers
M &lt;1 = 30°, m&lt; 2 = 45°, m&lt;3=
Papessa [141]
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7 0
3 years ago
The hours of daylight, y, in Utica in days x from January 1, 2013 can be modeled by the equation y = 2.89sin(0.0145x-1.40) + 10.
Pie

Answer:

9.3 hours

Step-by-step explanation:

Given

y = 2.89\sin(0.0145x-1.40) + 10.99.

Required

Hours of sunlight on Feb 21, 2013

First, calculate the number of days from Jan 1, 2013 to Feb 21, 2013

days = 52

So:

x = 52

So, we have:

y = 2.89\sin(0.0145x-1.40) + 10.99.

y = 2.89\sin(0.0145*52-1.40) + 10.99.

y = 2.89\sin(0.754-1.40) + 10.99.

y = 2.89\sin(-0.646) + 10.99.

y = 2.89*-0.6020 + 10.99.

y = -1.740 + 10.99.

y = 9.25

<em></em>y = 9.3<em> --- approximated</em>

8 0
2 years ago
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