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4 years ago

A gargoyle statue falls off the side of a building from a height of 75 m . How long did it take to reach the ground

Physics

1 answer:

disa [49]4 years ago

7 0

Distance of a fall from rest = (1/2) (g) (Time²)

75 m = (1/2) (9.8 m/s²) (Time²)

75 m = (4.9 m/s²) (Time²)

Divide each side by (4.9 m/s²):

Time² = (75 m) / (4.9 m/s²)

Time² = (15.3) (s²)

Square-root both sides:

<em>Time = 3.91 seconds</em>

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On a hot summer day a young girl swings on a rope above the local swimming hole. when she lets go of the rope her initial veloci

weqwewe [10]

Refer to the diagram shown below.
h = height of the girl above water when she lets go of the rope.

The launch velocity is 22.5 m/s at 35° to the horizontal. Therefore the vertical component of the velocity is
v = 22.5 sin(35°) = 12.9055 m/s.

The time of flight is t = 1.10 s before the girl hits the surface of the water at a height of -h.
Therefore
-h = (12.9055 m/s)*(1.10 s) - (1/2)*(9.8 m/s²)*(1.10 s)²
-h = 8.267 m
= 8.3 m (nearest tenth)

Answer:
When the girl let go of the rope, she was about 8.3 m above the surface of the water.

5 0

4 years ago

While on a weekend trip to New York Cily. You So! Angelina

liubo4ka [24]

Answer:

429.3 m

Explanation:

Speed=Distance÷Time

⇒Speed×Time=Distance

In this case,

Distance=27×15.9

=429.3m

Hope it helps.

6 0

4 years ago

All living things are made up of how many cells? Question 1 options: one or more two or more three or more many

MrRissso [65]

1) One or more

2) It can reproduce quickly

3) Unicellular organisms

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3 years ago

Read 2 more answers

Improving muscular strength and endurance slows bone density loss. Tf

hram777 [196]

true.A study has been conducted and suggested that indeed improving muscular strength and endurance or exercising can enhance bone density and stop it from declining whether its due to accidents or old age. Also, because this practice is needed to have stronger and more healthier bones, exercising is always a necessity and should be a habit.

Read more on Brainly.com - brainly.com/question/1169710#readmore

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3 years ago

Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A ther

kherson [118]

Answer:

So the 97 percentile for this case should be 1.88 degrees.

Explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the temperatures of a population, and for this case we know the distribution for X is given by:

$X \sim N(0,1)$

Where $\mu=0$ and $\sigma=1$ .

And we want the top 97 percentile for the distribution, so we need a value a such that:

$P(X>a)=0.03$ or $P(X$

We need on the right tail of the distribution a value a that gives to us 97% of the area below and 3% of the area above. Both conditions are equivalent.

Let's use the condition $P(X$ , the best way to solve this problem is using the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

So we need a value from the normal standard distribution that accumulates 0.97 of the area on the left and 0.03 on the right. This value on this case is 1.88 and we can founded with the following code in excel:

"=NORM.INV(0.97,0,1)"

The figure attached gives an approximation of the value and we can see that is near 1.88.

If we apply the z score formula to our case we have this:

$P(X$