Help me please with this

Which formula can be used to find the tangential speed of an orbiting object?

Luden [163]

The correct formula for calculating the tangential speed of an orbiting object is V(t)=wr.
V(t)= Tangential Speed
w= Angular Velocity
r= Radius of the Path

Hope this helps.

6 0

3 years ago

Read 2 more answers

A hard drive disk rotates at 7200 rpm. The disk has a diameter of 5.1 in (13 cm). What is the speed of a point 6.0 cm from the c

ExtremeBDS [4]

Answer:

The speed will be "3.4×10⁴ m/s²".

Explanation:

The given values are:

Angular speed,

w = 7200 rpm

i.e.,

= $7200 \times \frac{2 \pi}{60}$

= $753.6 \ rad/s$

Speed from the center,

r = 6.0 cm

As we know,

⇒ Linear speed, $v=wr$

On putting the estimated values, we get

$=753.6\times 0.06$

$=45.216 \ m$

Now,

Acceleration on disk will be:

⇒ $a=\frac{v^2}{r}$

$=34074 \ m/s^2$

$=3.4\times 10^4 \ m/s^2$

3 0

3 years ago

When the cylinder is displaced slightly along its vertical axis it will oscillate about its equilibrium position with a frequenc

Nesterboy [21]

Answer:

w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

Explanation:

We can simulate this system as a physical pendulum, which is a pendulum with a distributed mass, in this case the angular velocity is

w² = mg d / I

In this case, the distance d to the pivot point of half the length (L) of the cylinder, which we consider long and narrow

d = L / 2

The moment of inertia of a cylinder with respect to an axis at the end we can use the parallel axes theorem, it is approximately equal to that of a long bar plus the moment of inertia of the center of mass of the cylinder, this is tabulated

I = ¼ m r2 + ⅓ m L2

I = m (¼ r2 + ⅓ L2)

now let's use the concept of density to calculate the mass of the system

ρ = m / V

m = ρ V

the volume of a cylinder is

V = π r² L

m = ρ π r² L

let's substitute

w² = m g (L / 2) / m (¼ r² + ⅓ L²)

w² = g L / (½ r² + 2/3 L²)

L >> r

w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

4 0

4 years ago

Carry out the following arithmetic operations. (Enter your answers to the correct number of significant figures.) My Notes Ask Y

morpeh [17]

Answer :

(a) The answer will be $\Rightarrow 562$

(b) The answer will be $\Rightarrow 2.0$

(c) The answer will be $\Rightarrow 49.32$

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

(a) The sum of the measured values 521, 31.4, 0.85, and 9.0

$521+31.4+0.85+9.0$

$\Rightarrow 562.25$

In the given expression, 521 has 3 significant figures, 31.4 has 3 significant figures, 0.85 has 2 significant figures and 9.0 has 2 significant figures. From this we conclude that least precise number present after the decimal point is 0.

Thus, the answer will be $\Rightarrow 562$

(b) The product 0.0052 × 386.2

$(0.0052)\times (386.2)$

$\Rightarrow 2.00824$

In the given expression, 0.0052 has 2 significant figures and 386.2 has 4 significant figures. From this we conclude that 2 is the least significant figures in this problem. So, the answer should be in 2 significant figures.

Thus, the answer will be $\Rightarrow 2.0$

(c) The product $15.70\times \pi$

The value of $\pi$ = 3.141414 = $3.\bar {14}$

$\pi$ is an irrational number.

$(15.70)\times (3.1414)$

$\Rightarrow 49.31998$

In the given expression, 15.70 has 4 significant figures and $3.\bar {14}$ has infinite significant figures. From this we conclude that 4 is the least significant figures in this problem. So, the answer should be in 4 significant figures.

Thus, the answer will be $\Rightarrow 49.32$

3 0

4 years ago

As a person squeezes and applies pressure to the outside of a balloon, air particles inside

mixas84 [53]

The air particle inside the balloon will collide more with each other and the temperature inside the balloon will increase.

As a person squeezed and applies the pressure to the outside of a balloon, the air particle inside the balloon gains energy and collide with each other, the particle of the air also try leave the balloon surface will implies equal pressure on the wall of the balloon, as the pressure outside the balloon increase, the inside pressure will also increase.

7 0

3 years ago