1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nexus9112 [7]
4 years ago
8

A 13 kg rock is sitting on a cliff. If the rock has 3,500 joules of potential energy, what is the height of the cliff in meters?

(Round the answer to the nearest tenth. Show work
Physics
1 answer:
Bezzdna [24]4 years ago
7 0

<u>Answer:</u>

The height of the cliff in meters = 27.44

<u>Explanation:</u>

 The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

 Here we have mass of rock = 13 kg

                          Potential energy = 3500 J

                          Acceleration due to gravity  = 9.81m/s^2

                          Substituting   3500 = 13 * 9.81 * h

                                                       h = 27.44 meter

      The height of the cliff in meters = 27.44

You might be interested in
Imagine whirling a ball on a string over you head. Suppose the knot holding the ball comes loose and the ball is instantly relea
zaharov [31]

B is the answer to the question

8 0
3 years ago
When water change into ice it contracts or expand<br> plz answer fast..
mihalych1998 [28]

Answer:Yes, water indeed expands when it changes form from liquid to solid. And this is because water has a property called “hydrogen bonds”, and these bonds occur between each water molecule. But when water is in a liquid form these hydrogen bonds break more easily and occur less frequently. When the temperature drops the kinetic energy also drops, which in turn makes hydrogen bonds form more frequently. So the water molecules form a lattice, which is less dense than regular liquid water.

Explanation:

4 0
3 years ago
Read 2 more answers
The force required to maintain an object at a constant velocity in free space is equal to
alex41 [277]

Answer:

The force required to maintain an object at a constant velocity in free space is equal to Zero.

7 0
3 years ago
Mitochondria are responsible for
Inessa [10]
Breaking down energy into food
5 0
3 years ago
Where is the best place to put pfds while you are out on your boat?
Alexeev081 [22]
The best place to put PFDs while you are out on your boat is at the top deck of your boat. PFDs must be placed at an area where it is easily accessible, especially in times of accidents, without any unnecessary gear or objects covering the PFDs, but it is best to wear a life jacket during the whole duration of the boat trip.
3 0
4 years ago
Other questions:
  • A tank of liquid (SG=0.80) that is 1 ft in diameter and 1.0 ft high is rigidly fixed to a rotating arm having a 2 ft radius. The
    7·1 answer
  • The velocity of a car changes from 50 m/s north to 40 m/s north in 2 seconds. What is the car’s acceleration?
    15·1 answer
  • Calculate the wavelength of violet light with a frequency of 750×10 to the 12
    12·2 answers
  • A 100-turn, 2.0-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 60∘ away from vertical increases fro
    8·1 answer
  • What direction does air resistance act on an object that is falling straight down
    15·1 answer
  • Two waves have the same speed. the first has twice the frequency of the second. compare the wavelengths of the two waves. 1. the
    12·1 answer
  • Consider a ball (with moment of inertia I=2/5MR^2) which bounces elastically
    12·2 answers
  • A turtle accelerates from a stop at 3 m/s^2 to the south for 8s. what is the turtles final velocity
    13·1 answer
  • A 0.0600-kilogram ball traveling at 60.0 meters per second hits a concrete wall. What speed must a 0.0100-kilogram bullet have i
    7·1 answer
  • Help i need to answer this question fast​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!