<span>It takes 6.78 seconds for the coin to hit the bottom of the well. We can use the equation h = 0.5gt^2, where h is the height of the coin, g is the gravitational constant of 9.8m/s^2, and t is the time is takes for the coin to hit the bottom of the well. Solve for t to obtain 6.87 seconds.</span>
Answer:
v = √ 2e (V₂-V₁) / m
Explanation:
For this exercise we can use the conservation of the energy of the electron
At the highest point. Resting on the top plate
Em₀ = U = -e V₁
At the lowest point. Just before touching the bottom plate
Emf = K + U = ½ m v² - e V₂
Energy is conserved
Em₀ = Emf
-eV₁ = ½ m v² - e V₂
v = √ 2e (V₂-V₁) / m
Where e is the charge of the electron, V₂-V₁ is the potential difference applied to the capacitor and m is the mass of the electron
Started at 4.30 p.m ,15+45+30=1 hr 30 mins,6.00-1 hr 30 mins=4.30 p.m
Make the foundation more sturdy
Explanation:
The classic model of a black body made predictions of the emission at small wavelengths in open contradiction with what was observed experimentally, this led Planck to develop a heuristic model. This assumption allowed Planck to develop a formula for the entire spectrum of radiation emitted by a black body, which matched the data.
