This is not true. The infinite series

converges if and only if the sequence of its partial sums converges. The

-th partial sum is

but clearly this diverges as

gets arbitrarily large.
Answer:
In order to calculate the expected value we can use the following formula:
And if we use the values obtained we got:
Step-by-step explanation:
Let X the random variable that represent the number of admisions at the universit, and we have this probability distribution given:
X 1060 1400 1620
P(X) 0.5 0.1 0.4
In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".
The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).
And the standard deviation of a random variable X is just the square root of the variance.
In order to calculate the expected value we can use the following formula:
And if we use the values obtained we got:
Answer:
Lo siento. :(
Step-by-step explanation:
Me preguntaba lo mismo. Desearía poder ayudar, pero también necesito ayuda.
The complete question is as follows.
The equation a =
can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths,
and
. Which are equivalent equations?
(a) 
(b) 
(c)
= 
(d) 
(e)
= h
Answer: (a)
; (d)
;
Step-by-step explanation: To determine
:
a = 
2a = (
)h


To determine h:
a = 
2a = 
= h
To determine 
a = 
2a = 


Checking the alternatives, you have that
and
= h, so alternatives <u>A</u> and <u>D</u> are correct.
Answer:
i11, i26, i20, i21
Step-by-step explanation:
Alright, so there's an order to imaginary numbers. At the 1st power, it's i. At the second, it's -1. At the 3rd, it's -i. At the 4th, it's 1. And at the 5th, it restarts.