Four different ways to solve a quadratic equation are factoring, completing the square, quadratic formula, and graphing. all methods start with setting the equation equal to zero.

to determine the zeros of a quadratic graph, find the points where the graph of the quadratic equation crosses the x-axis. to determine the vertex, you convert the quadratic form to vertex form, you use this process of completing the square. to determine the axis of symmetry, you cut the graph vertically to see the symmetrical sides.

hope this helps, God bless!

8 0

2 years ago

Emanuel was charged $32 for a 14 2/9 km taxi ride. What was the cost per kilometer?

padilas [110]

32 / (14 2/9) =
32 / (128/9) =
32 * 9 / 128 =
288 / 128 =
$ 2.25 per km

4 0

2 years ago

Read 2 more answers

Jack and Jane are married and both work. However, due to their responsibilities at home, they have decided that they do not want

Zanzabum

To solve a system of inequalities we graph both of them.
The inequality representing their combined pay would be
$12.50x+10.00y \geq 750$ . This is because Jane makes 12.50/hr, Jack makes 10.00/hr, and they want to make at least, so greater than or equal to, $750 combined.
The inequality representing their combined hours working would be
$x+y \leq 65$ , since they do not want their combined hours to be over 65. In both of these inequalities, x represents the number of hours Jane works and y represent the number of hours Jack works.
To graph these, we solve both of them for y:
$x+y \leq 65
\\ x+y-x \leq 65-x
\\ y \leq 65-x$
$12.50x+10.00y \geq750
\\12.50x+10.00y-12.50x \geq 750-12.50x
\\10.00y \geq 750-12.50x
\\ \frac{10.00y}{10.00} \geq \frac{750}{10.00} - \frac{12.50x}{10.00}
\\y \geq 75-1.25x$
The attached screenshot shows what the graph looks like. Going to the point where they intersect, we see that the shaded region that satisfies both inequalities begins when Jane works 40 hours and Jack works 25.

5 0

2 years ago

The fastest human has ever run is 27 mph how many miles per minute did the human run

Phoenix [80]

$\sf \frac{27~ miles}{1 ~hour} \times \frac{1~ hour}{60~ minutes} = \boxed{\frac{9}{20}~miles~per~minute}$

7 0

2 years ago