(x-h)^2 + (y-k)^2 = r^2
(x-2)^2 + (y-0)^2 = (rt(5))^2
-h = -2
h = 2
k=0
Center(2, 0)
Additive Identity Property is the answer.
Answer:
1. e
2. c
Step-by-step explanation:
1. e. table
The question displays a table that organizes the data
2. c
When you compare the x and y values of a relationship, in this case the b and t variables, you use a ratio.
X= -4y let this be equation 1
x+5y=2 let this be equation 2
substitute equation 1 in 2
-4y + 5y = 2
y=2
substitute the value of y in equation 1
x= -4y
x= -4(2)
x= -8
Perpendicular because y=1 goes across and x=1 goes vertical forming a right angle
