Question

What is the value of ?

Answer 1

Remember
$\frac{x^m}{x^n}=x^{m-n}$
and
$x^{-m}=\frac{1}{x^m}$

so
$\frac{3^2}{3^4}=3^{2-4}=3^{-2}=\frac{1}{3^2}=\frac{1}{9}$