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Veseljchak [2.6K]
3 years ago
10

What is the value of ?

Mathematics
1 answer:
Ede4ka [16]3 years ago
5 0
Remember
\frac{x^m}{x^n}=x^{m-n}
and
x^{-m}=\frac{1}{x^m}

so
\frac{3^2}{3^4}=3^{2-4}=3^{-2}=\frac{1}{3^2}=\frac{1}{9}
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Find the slope of the line that passes through the points (-19, -4) and (13, -17).​
Tasya [4]

Answer:

m = \frac{-13}{32}

Step-by-step explanation:

Two point slope formula = \frac{y_{2} - y_{1}  }{x_{2} - x_{1} }

\frac{-17 + 4}{13 + 19} = \frac{-13}{32}

7 0
3 years ago
Read 2 more answers
Which is the solution to the inequality? y minus 27 greater-than-or-equal-to negative 13 y greater-than-or-equal to negative 40
djyliett [7]

Answer:

y\geq 14

y greater than or equal to 14

Step-by-step explanation:

Given the inequality:

y-27\geq -13

We solve it by isolating the variable y on one side. That is, in our case we add 27 to both sides and get:

y-27\geq -13\\y\geq 27-13\\y\geq 14

3 0
3 years ago
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For each of the following, decide whether the description fits the SD or the SE.
Anna71 [15]
The answer is B because the quantity tends to stay the same as the sample goes up
3 0
3 years ago
Please help again, best answer = brainliest
tangare [24]
I think the answer would be B :)
4 0
3 years ago
A. f(x) = l-2xl - 3<br> Domain: {1, 2, 3}<br> Find the range
gizmo_the_mogwai [7]

Hello there!

We are given the function:

\displaystyle \large{ f(x) =  | - 2x|  - 3} \\

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

<u>x</u><u> </u><u>=</u><u> </u><u>1</u>

\displaystyle \large{ f(1) =  | - 2(1)|  - 3} \\   \displaystyle \large{ f(1) =  | - 2|  - 3} \\

Recall that any numbers in absolute value are always positive.

\displaystyle \large{ f(1) =  2 - 3} \\   \displaystyle \large{ f(1) =   - 1} \\

<u>x</u><u> </u><u>=</u><u> </u><u>2</u>

\displaystyle \large{ f(2) =  | - 2(2)|  - 3} \\   \displaystyle \large{ f(2) =  | - 4 |   - 3} \\   \displaystyle \large{ f(2) =  4 - 3} \\   \displaystyle \large{ f(2) =  1}

<u>x</u><u> </u><u>=</u><u> </u><u>3</u>

\displaystyle \large{ f(3) =  | - 2(3)|  - 3} \\   \displaystyle \large{ f(3) =  | - 6|   - 3} \\   \displaystyle \large{ f(3) =  6 - 3} \\   \displaystyle \large{ f(3) =  3}

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0
3 years ago
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