B. 42 degrees
Angle ABC is an inscribed angle so u have to divide Arc AC by 2 to find angle ABC.
84degrees divided by 2 is 42 degrees.
<span>(a) This is a binomial
experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer
than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
Answer:
f(-7) = 268
Step-by-step explanation:
f(x) = 4x^2 – 10x + 2
Let x = -7
f(-7) = 4(-7)^2 – 10(-7) + 2
Exponents first
f(-7) = 4(49) – 10(-7) + 2
Multiply
f(-7) = 196 + 70 + 2
f(-7) = 268
Answer:
The tallest column of the line plot
Step-by-step explanation:
A line plot shows the frequency of data, in short it shows how many times something has occurred or the number of times data occurs in a group of data.
The number of data is represented by markers or in this case "x"s. The more x's along the column, the more times it occurred.
The bar graph there does not show the frequency of the different scores. This shows the relationship between the test number and the percentage of the scores obtained. It does not tell you the individual scores obtained.
