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SOVA2 [1]
3 years ago
9

HELP PLEASE ILL GIVE BRAINLIEST

Mathematics
1 answer:
iren [92.7K]3 years ago
3 0

The surface of the triangle count formula

A = b*h*1/2

A - area

b - base

c - height

The 1st triangle

A₁ = b₁*h = 6in * 8in *1/2= 24in²


The 2nd triangle

A₂ b₂*h = 10in * 8in*1/2 = 40in²


The total area of the two triangles is 24in² + 40in² = 64 square inches





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Answer:

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The general solution values  

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Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

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Dividing '2' on both sides, we get

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                             cos x = cos(\frac{\pi }{6})

<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}

x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

                               

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