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taurus [48]
3 years ago
11

Solve the following system of equations. Express your answer as an ordered pair in the format (a,b), with no spaces between the

numbers or symbols.
2x+5y=16
-5x-2y=2
Mathematics
1 answer:
kirill [66]3 years ago
6 0

Answer:

\huge\boxed{(2,4)}

Step-by-step explanation:

2x + 5y = 16 ------------------(1)

-5x -2y = 2   ------------------(2)

<u>Multiplying (1) by 5 </u>

5(2x+5y) = 16*5

10x+25y = 80 ----------------(3)

<u>Multiplying (2) by 2</u>

2(-5x-2y) = 2*2

-10x - 4y = 4 -----------------(4)

Adding Eq. (3) and (4)

10x + 25y -10x -4y = 80 + 4

25y - 4y = 84

21y = 84

Dividing both sides by 21

y = 4

\rule[225]{225}{2}

Now, Putting y = 4 in Eq. (1)

2x + 5(4) = 16

2x + 20 = 16

2x = 20 - 16

2x = 4

Dividing both sides by 2

x = 2

\rule[225]{225}{2}

Ordered Pair = (x,y) = (a,b) = (2,4)

\rule[225]{225}{2}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
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spayn [35]

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4 0
3 years ago
What is the value of the expression below when y 8 and z = 8? 9y + 3z​
aleksley [76]

Answer:

96

Step-by-step explanation:

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6 0
3 years ago
Triangle ABC is shown below.
Andrew [12]

Answer:

C.) 14

Step-by-step explanation:

Look at the triangle: angles b and c have the same arch, so they are congruent.

In a triangle, if two angles are congruent, then the triangle is isosceles, having two equal sides.

The sides opposite the congruent angles are congruent:

∠B → opposite side → AC

∠C → opposite side → AB

The sides AB and AC are equal. Make an equation:

AB=AC\\\\2x=3x-7

Simplify the equation, solving for x. Add 7 to both sides:

2x+7=3x-7+7\\\\2x+7=3x

Subtract 2x from both sides:

2x-2x+7=3x-2x\\\\7=x

The value of x is 7. Insert the value of x into the given length of AC:

AC=3(7)-7

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AC=21-7

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Therefore, the length of the line segment AC is 14.

:Done

8 0
3 years ago
Could someone please explain to me how to determine the answer to this question?
dexar [7]

Concept: Solution of the given attachment is based on the addition of two vectors as given below.

Consider two vectors P and Q, then resultant of these two vectors is given as,

R = P + Q

To find the addition of G & H vectors. That is G + H =?

In the given figure;

Vector A = - Vector G because both are in opposite directions -----(i)

From the figure,

A + H = F --------------- using the given concept ---------(ii)

Now, shall replace the value of A from equation (i) in equation(ii)

- G + H = F

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6 0
4 years ago
New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.
elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0
3 years ago
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