The wetter the surface, the friction

Which action can be explained by physics?

steposvetlana [31]

Answer:

Actions that underlie mathematical rules, patterns or probability distributions.

For example how fast something falls at any given point or time.

More complex actions, such as human decision making in single individuals would be way too complicated to describe in physical terms.

But note that there can be physical models of such things as traffic when we can assume statistical knowledge of behavior.

Also physical models are used to plan such things as emergency exits in big stadiums, because many thousands of people can be described as particles flowing under a given pressure.

Every time we can gain good statistical knowledge and can therefore see patterns and rules in action, we can build theoretical models to make predictions and simulations (and games btw)

Since it's fair to say that mathematics is the science of patterns, it is plausible that physical descriptions often come in mathematical formulations, so that it can be understand as an efficient language of physics.

Neighboring disciplines like chemistry relay on physical theories to build on them,and then add shortcuts to fit their needs and interests, generating an own language for their field of study. But physicists may refer to them as anadd-on to physics.

Physics can basically explain all actions wich you can express in numbers.

But note that on a fundamental level physics describes 'how' things work, not necessarily 'why' they do it this way. The source of the basic and most fundamental physical constants and rules remains a mystery till this day.But of course there are theories on that as well, wich mostly can neither be proved or falsified.

The text is my own work and based of my general knowledge and quintessence of lectures on physics and other fields I attended.

(I would really appreciate the brainliest)

3 0

3 years ago

What is the difference between speed and velocity ?

gizmo_the_mogwai [7]

Speed is the distance traveled
time
but velocity is the change in distance
time

7 0

3 years ago

Read 2 more answers

A trombone plays a C3 note. If the speed of sound in air is 343 m/s and the wavelength of this note is

Umnica [9.8K]

The frequency of note C3 is 131 $s^{-1}$ .

<u>Explanation:</u>

Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.

And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.

Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

$Frequency=\frac{speed of sound}{Wavelength of note}$

Thus,

$Frequency = \frac{343 m/s}{2.62 m} = 131 s^{-1}$

So the frequency of note C3 is 131 $s^{-1}$ .

3 0

3 years ago

Which of the following statements is TRUE concerning forces?

Gnesinka [82]

The answer is d I took the test

3 0

3 years ago

vA 61.2-kg circus performer is fired from a cannon that is elevated at an angle of 57.8 ° above the horizontal. The cannon uses

dsp73

Answer:

The effective spring constant of the firing mechanism is 1808N/m.

Explanation:

First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

$v_0_x=\frac{x}{t}\\ \\v_0\cos\theta=\frac{x}{t}\\\\v_0=\frac{x}{t\cos\theta}$

(This is correct because the horizontal motion has acceleration zero). Then:

$v_0=\frac{20.8m}{(2.60s)\cos57.8\°}\\\\v_0=15.0m/s$

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

$E_0=E_f\\\\U_e=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\\implies k=\frac{mv^2}{x^2}$

Then, plugging in the given values, we obtain:

$k=\frac{(61.2kg)(15.0m/s)^2}{(2.76m)^2}\\\\k=1808N/m$

Finally, the effective spring constant of the firing mechanism is 1808N/m.

3 0

3 years ago