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HACTEHA [7]
3 years ago
12

What is the average speed of a car that travelled 400 miles in 6 hours?

Physics
2 answers:
Reil [10]3 years ago
8 0

Answer:

About 66 miles per hour

Explanation:

Based on the information given we can assume the car traveled the same number of miles every hour meaning all we need to do is divide.

400/6 ≈ 66 miles per hour

Ahat [919]3 years ago
7 0

Answer

66 mph

Explanation:

400 ÷ 6 = 66.666666666666666.......

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an object is tossed upwards with the same inital velocity on the earth then on the moon . will the max
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The one tossed upward on the Moon will rise to a greater maximum height before starting to fall.  

It'll also spend more total time in flight before returning to the hand that tossed it. (I almost said that it'll spend "more time in the air".  That would be silly on the Moon.)

6 0
3 years ago
An athlete competing in long jump leaves the ground with a speed of 9.14 m/s at an angle of 35.00 above the horizontal. What is
Lemur [1.5K]

Answer:

      R = 8.01 m

Explanation:

We can solve this problem using the projectile launch equations. The jump length is the throw range

           R = v₀² sin  2θ / g

in the exercise they give us the initial speed of 9.14 m / s and in the launch angle 35º

let's calculate

           R = 9.14² sin (2  35) / 9.8

           R = 8.01 m

this is the jump length

5 0
2 years ago
How did scientists determine the age of the ocean floor
Umnica [9.8K]

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6 0
3 years ago
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E = mgh = 70*10*10 = 7000J
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3 years ago
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Two objects each moving with speed v travel in opposite directions along a straight line passing through both their centers. The
Tpy6a [65]

Answer:

\dfrac{1}{16}

\dfrac{5}{3}

Explanation:

m_1 = Mass of first object

m_2 = Mass of second object

v = Speed of both objects

\dfrac{v}{4} = Combined velocity

The ratio of final kinetic energy to initial kinetic energy will be

\dfrac{K_f}{K_i}=\dfrac{\dfrac{1}{2}(m_1+m_2)(\dfrac{v}{4})^2}{\dfrac{1}{2}(m_1v^2+m_2v^2)} \\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{(m_1+m_2)\dfrac{v^2}{16}}{m_1v^2+m_2v^2}\\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{(m_1+m_2)\dfrac{1}{16}}{m_1+m_2}\\\Rightarrow \dfrac{K_f}{K_i}=\dfrac{1}{16}

The ratio is \dfrac{1}{16}

As the linear momentum is conserved

m_1v-m_2v=(m_1+m_2)\dfrac{v}{4}\\\Rightarrow m_1-m_2=(m_1+m_2)\dfrac{1}{4}

Divide by m_2 on both sides

\dfrac{m_1}{m_2}-1=\dfrac{m_1}{4m_2}+\dfrac{1}{4}\\\Rightarrow \dfrac{m_1}{m_2}-\dfrac{m_1}{4m_2}=\dfrac{1}{4}+1\\\Rightarrow \dfrac{3m_1}{4m_2}=\dfrac{5}{4}\\\Rightarrow \dfrac{m_1}{m_2}=\dfrac{5\times 4}{3\times 4}\\\Rightarrow \dfrac{m_1}{m_2}=\dfrac{5}{3}

The ratio of mass is \dfrac{5}{3}

6 0
3 years ago
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