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12345 [234]
3 years ago
7

The system needs an ordinary friction-based brake to bring the train to a full stop. Explain why the magnetic brake is not very

efficient when the train is moving slowly. The system needs an ordinary friction-based brake to bring the train to a full stop. Explain why the magnetic brake is not very efficient when the train is moving slowly. The slower the train is moving, the greater are the changes of the magnetic flux, thus the eddy currents become stronger. The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker. The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become stronger. The slower the train is moving, the greater are the changes of the magnetic flux, thus the eddy currents become weaker.
Physics
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:

The slower the train is moving, the less are the changes of the magnetic flux, thus the eddy currents become weaker.

Explanation:

A magnetic brakes is not a very efficient way of braking when a train is moving slowly because at low speeds, the changes in the magnetic flux are very less and so it causes the eddy current to become weaker.

Let us find the drag force which is proportional to the velocity of two conducting plates.

The EMF that is induced in the eddy currents are : $E=v(B \times L)$

The force which is due to the induced magnetic field is, $F=l(L \times B)$

Therefore, $F=\frac{E}{R} \times (L \times B)$

                 $F=\frac{v(B \times L)}{R} \times (L \times B)$

Here, force is directly proportional to the velocity of the two conducting plates.

Therefore, we can say that when the speed of the train is low, the magnetic flux changes are less and thus the eddy currents are weaker.  

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A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point
Nonamiya [84]

Answer:

1.52 m

Explanation:

We are given that

Maximum force=F=679 N

Mass of rock ,m=385 kg

Distance,d=0.233 m

We have to find the  minimum total length L of the rod required to move the rock.

Torque on rock=T_1=mgd=385\times 9.8\times 0.233=879.11 N

Where g=9.8m/s^2

Torque on man=T_2=Force\times distance=(L-d)\times 679=(L-0.233)\times 679

T_1=T_2

(L-0.233)\times 679=879.11

L-0.233=\frac{879.11}{679}=1.29

L=1.29+0.233=1.523\approx 1.52 m

Hence, the minimum total  length of rod=1.52 m

3 0
3 years ago
Xenon hexafluoride was one of the first noble gas compounds synthesized. The solid reacts rapidly with the silicon dioxide in gl
Oxana [17]

Answer:

0,93 atm

Explanation:

For this we will use PV = nRT

P is what we want to find

V = 1 L

n = \frac{8.53}{223.23} = 0,038 moles

R = 0,082 \frac{L atm}{K mole}

T = 25°C = 298,15 K

P * 1 = 0,038 *0,082 * 298,15

P = 0,93 atm

5 0
3 years ago
The work energy principle states that the change in kinetic energy of an object is equal to the net work done on the object. If
sattari [20]

Answer:

v=\sqrt{2gh}\ m/s

Explanation:

From work energy theorem

Work done by all forces = Change in kinetic energy

Lets take

m= mass of object

h=height from the ground surface

initial velocity of object = 0 m/s

The final velocity of object is v

Work done by gravitational force = m g . h

The final kinetic energy = 1/2 m v²

So

Work done by all forces = Change in kinetic energy

m g h =  1/2 m v² - 0

v² = 2 g h

v=\sqrt{2gh}\ m/s

6 0
4 years ago
When the moon slowly moves away from the earth.How is it affecting the gravitational force between the earth and the moon?
sukhopar [10]
Well, think about how the tides will be affected when the moon moves farther away. If the moon first started off very close the earth, we would have more tsunamis. (Scientists have found that the moon has possibly been closer to earth long ago.) While it moves away, soon there will no longer be many tides.
3 0
3 years ago
How much electrical energy is used by a 400 W toaster that is operating for 5 minutes?
Shkiper50 [21]

The electrical energy consumed by a toaster is 0.033 Kwh.

<u>Explanation</u>:

The power utilized by the toaster is 400 W.

\text { The power utilized by the toaster is } 400 \mathrm{W} \text { in kilo-watts is } \frac{400}{1000}=0.4 \mathrm{Kw}

The toaster is operated for 5 Minutes.

\text { The toaster is operated for } 5 \text { Minutes in hours is } \frac{5}{60}=0.083 \text { hours. (One minute is } 60 \text { seconds) }

We know that,

\text {power}=\frac{\text {energy}}{\text {time}}

Substitute the values in the above formula to obtain electrical energy,

0.4=\frac{\text { energy }}{0.083}

Electrical energy = 0.4 × 0.083

Electrical energy is 0.033 Kwh.

3 0
3 years ago
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