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IrinaVladis [17]
3 years ago
13

Un diapasón vibra a 140 [Hz] y la onda emitida por él se propaga con una rapidez de 340 m/s.Considerando lo anterior, se puede a

firmar correctamente que la longitud de onda de la onda emitida por el diapasón es
Physics
1 answer:
Gnom [1K]3 years ago
5 0

The question is: A tuning fork vibrates at 140 [Hz] and the wave emitted by it propagates with a speed of 340 m / s. Considering the above, it can be correctly stated that the wavelength of the wave emitted by the tuning fork is

Answer: Wavelength of the wave emitted by the tuning fork is 2.43 m.

Explanation:

Given: Frequency = 140 Hz

Speed = 340 m/s

wavelength = ?

Formula used to calculate the wavelength is as follows.

\lambda = \frac{v}{f}

where,

\lambda = wavelength

v = speed

f = frequency

Substitute the values into above formula.

\lambda = \frac{v}{f}\\= \frac{340 m/s}{140 Hz}  (1 Hz = 1 s^{-1})\\= 2.43 m

Thus, we can conclude that wavelength of the wave emitted by the tuning fork is 2.43 m.

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A thin layer of liquid methylene iodide (n = 1.756) is sandwiched between two flat, parallel plates of glass (n = 1.50). What mu
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Answer:

t = 96.1 nm

Explanation:

For strong reflection through liquid layer we know that the path difference between two reflected light rays must be integral multiple of wavelength

now we know that the path difference of two reflected light from thin liquid layer is given as

2\mu t - \frac{\lambda}{2} = N\lambda

here we know that

\mu = 1.756

t = thickness of layer

N = 0 (for minimum thickness of layer)

\lambda = 675 nm

now we have

2(1.756) t = \frac{675 nm}{2}

t = 96.1 nm

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3 years ago
A coin of mass m rests on a turntable a distance r from the axis of rotation. The turntable rotates with a frequency of f. What
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Answer:

\mu = \frac{r (2\pi f)^{2}}{g}

Explanation:

N = normal force acting on the coin

Normal force in the upward direction balances the weight of the coin, hence

N = mg

f = frequency of rotation

Angular velocity of turntable is hence given as

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r = distance from the axis of rotation

\mu = minimum coefficient of static friction

static frictional force is given as

f = \mu N\\f = \mu mg

The  static frictional force provides the necessary centripetal force , hence

Centripetal force = Static frictional force

m r w^{2} = \mu mg\\r w^{2} = \mu g\\\\\mu = \frac{r w^{2}}{g} \\\mu = \frac{r (2\pi f)^{2}}{g}

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3 years ago
A ride at an amusement park moves the riders in a circle at a rate of 6.0 m/s. If the radius of the ride is 9.0 meters, what is
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<span>4.0 m/s2


it's 9 squared divided by 6</span>
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When you drive through deep water, you should dry out your brakes by _____________. pumping your brakes and driving in low gear
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Answer:

By Applying pressure to the brakes

Explanation:

Driving cars through deep water that is more than 10cm can make the cars to float. Most modern cars are usually water- tight so they can start to float through water that is about 30cm deep, fast moving water is very powerful so one needs to be very careful when driving.

If the brakes are wet test them by pressing or tapping on them gently.

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3 years ago
The sound produced by the loudspeaker in the drawing has a frequency of 11999 Hz and arrives at the microphone via two different
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The speed at which sound travels through the gas in the tube is 719.94m/s

<u>Explanation:</u>

Given:

Frequency, f = 11999Hz

Wavelength, λ = 0.03m

Velocity, v = ?

Sound speed in the tube is calculated by multiplying the frequency v by the wavelength λ.

As the sound loudness changed from a maximum to a minimum, then we know the sound interference in the case changed from constructive interference (the two sound waves are in phase, i.e. peaks are in a line with peaks and so the troughs), to a destructive interference (peaks coinciding with troughs). The least distance change required to cause such a change is a half wavelength distance, so:

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v = 719.94m/s

Therefore, the speed at which sound travels through the gas in the tube is 719.94m/s

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3 years ago
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