Y= 3(3)–2(3)2+5(3)3
y= 9–2*3*2+5*9
y=9–12+5*9
y=9–12+45
y=42
If they're integers, that means they can't be fractions (such as 15/2 and 2).
So the only couples of integers that, when multiplied, result in 15 are:
1 and 15
5 and 3.
(there are no other possibilities as both 5 and 3 are not divisible further).
The smaller of the two sums (15+1; 5+3) is 5+3=8.
The least possible sum of a and b is 8.
not sure really what the question is asking but dividing both sides of the equation by "t" is:
Answer:
It is ................................................................. 1
Step-by-step explanation:
There are 52 cards in a deck, 54 including the jokers
