X=-2y+6
-2y+6+y=10
-y+6=10
-y=4
y=-4
X=14
2(14) + 2(-4)=28- -8=28+8=36
Answer is 36 I think
<u>Answer-</u>
- YZ = 9 cm
![XZ=9\sqrt2](https://tex.z-dn.net/?f=XZ%3D9%5Csqrt2)
- XZ is the longest segment in triangle XYZ.
<u>Solution-</u>
Triangle XYZ is a right angle triangle with ∠Y=90°
Triangle XYZ is also an isosceles triangle, as
∠X =45°= ∠Z
Therefore, triangle XYZ is a right angle isosceles triangle.
So,
XY = YZ = 9 cm
Applying Pythagoras theorem,
![\Rightarrow XZ^2=XY^2+YZ^2\\\\\Rightarrow XZ^2=9^2+9^2\\\\\Rightarrow XZ^2=2\times 9^2\\\\\Rightarrow XZ=\sqrt{2\times 9^2}=9\sqrt2](https://tex.z-dn.net/?f=%5CRightarrow%20XZ%5E2%3DXY%5E2%2BYZ%5E2%5C%5C%5C%5C%5CRightarrow%20XZ%5E2%3D9%5E2%2B9%5E2%5C%5C%5C%5C%5CRightarrow%20XZ%5E2%3D2%5Ctimes%209%5E2%5C%5C%5C%5C%5CRightarrow%20XZ%3D%5Csqrt%7B2%5Ctimes%209%5E2%7D%3D9%5Csqrt2)
In a right angle triangle, always the hypotenuse is the largest. So XZ is the longest segment in triangle XYZ.
Answer:
x = 16.6
Step-by-step explanation:
Since we know the measure of an acute angle (31 degrees) of a right angle triangle, and of the side opposite to the angle (10), and we need to find the measure of the adjacent side "x", we use the tangent function:
![tan(\theta) = \frac{opposite}{adjacent} \\tan(31^o)=\frac{10}{x}\\x=\frac{10}{tan(31^o)} \\x \approx 16.64279](https://tex.z-dn.net/?f=tan%28%5Ctheta%29%20%3D%20%5Cfrac%7Bopposite%7D%7Badjacent%7D%20%5C%5Ctan%2831%5Eo%29%3D%5Cfrac%7B10%7D%7Bx%7D%5C%5Cx%3D%5Cfrac%7B10%7D%7Btan%2831%5Eo%29%7D%20%5C%5Cx%20%5Capprox%2016.64279)
which rounded to one decimal is
x = 16.6
Answer:
20
Step-by-step explanation:
1449÷72.45=20
9.3 repeating is the answer.