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3 years ago

What can amber do to make sure no one else can access her document?

Computers and Technology

2 answers:

Lelu [443]3 years ago

7 0

Answer:

Amber needs to run with the document and hide it in a safe place so no one else can access her document:)

tigry1 [53]3 years ago

5 0

Amber can get a safe with a good password then hide the safe and nobody will access it, hope this helped :)

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Difference between volatile and non volatile memory

slega [8]

<span>Volatile memory requires electricity or some kind of current to store information, and nonvolatile memory does not.</span>

6 0

3 years ago

Read 2 more answers

To whom the script most important

baherus [9]

The scripter as he made the script.

5 0

3 years ago

Write a function that takes as input a single integer parameter n and computes the nth Fibonacci Sequence number. The Fibonacci

RSB [31]

Answer:

Following are the code to this question:

def Fibonacci(n):#defining a method Fibonacci that accept a parameter

a = 1#defining a variable a that holds a value 1

b = 1#defining a variable b that holds a value 1

if n <= 0:# Use if to check n value

print("invalid number")#print message

elif n == 2:#defining elif that check n equal to 2

return 1#return 1

else:#defining else block

print(a)#print value of a

print(b)#print value of b

for i in range(2,n):#defining for loop to calculate series

s = a + b# add value in s variable

a = b # interchange value

b = s# hold s value

print(s)#print s value

Fibonacci(10)#calling method

Output:

Explanation:

In the above-given program code, a method "Fibonacci" is defined, which holds a value "n" in its parameter, and inside the method two-variable "a and b" is defined, that holds a value "1".

In the next step, if a block is defined that checks n value is less than equal to 0, it will print "invalid number" as a message.
In the elif, it checks n value is equal to 2 it will return a value that is 1.
In the else block, it will calculate the Fibonacci series and print its value.

4 0

3 years ago

You’ve been stuck in bumper-to-bumper traffic for nearly an hour on a hot summer day. The temperature warning light has just com

nekit [7.7K]

Answer:

In a bumper-to-bumper traffic, when the engine starts overheating the situation can be handled by tapping the accelator which will revive the engine.

Explanation:

Overheating of engine can be due to many reasons. But one should know what to do when an engine overheats in a traffic. Bumper-to-bumper traffic is when the cars are so close in traffic that they touch each other. This usually happens when there's a traffic for a long time or on very busy lane. During summer times, it is important to keep checking the engine temperature to avoid any problem.

When one is stuck in bumper-to-bumper traffic with overheating engine, then there are some meausres that one can take. They are:

To put the car on park or neutral mode of driving and tap the accelator which will revive the engine.
The heat can be disperse by rolling down the window and turn the heater up. It will disperse the heat.

6 0

3 years ago

Complete the getNumOfCharacters() method, which returns the number of characters in the user's string. We encourage you to use a

photoshop1234 [79]

Answer:

The Java code is given below with appropriate comments

Explanation:

//Program

//Import the necessary libraries

import java.util.Scanner;

//Define the class

public class CountStringCharacters

{

//Start the main method

public static void main(String[] args)

{

//Prompt the user to enter the input line

Scanner scan = new Scanner(System.in);

System.out.println("Enter a sentence or phrase: ");

String s = scan.nextLine();

//Take the number of characters and keep the count

int numOfCharacters = getNumOfCharacters(s);

System.out.println("You entered: "+s);

System.out.println("Number of characters: "+numOfCharacters);

//Call the method outputWithoutWhitespace

outputWithoutWhitespace(s);

}

//The method getNumOfCharacters

public static int getNumOfCharacters(String s)

{

int numOfCharCount = 0;

for(int i=0; i<s.length();i++)

{

numOfCharCount++;

}

return numOfCharCount;

}

//Definition of the method outputWithoutspace

public static void outputWithoutWhitespace(String s)

{

String str = "";

for(int i=0; i<s.length();i++)

{

char ch = s.charAt(i);

if(ch != ' ' && ch != '\t')

str = str + ch;

}

System.out.println("String with no whitespace: "+str);

}

5 0

3 years ago