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Alekssandra [29.7K]
4 years ago
8

A farmer is placing fencing material around her triangular garden. The vertices of her garden are located at the points (−1, 5),

(4, 2), and (9, −4) on a coordinate grid. If each unit on the grid represents a foot and the material costs $8 per foot, how much will she pay for the material on the side between points (−1, 5) and (4, 2)?
Mathematics
1 answer:
Lilit [14]4 years ago
8 0

Answer:

Cost= \$47

Step-by-step explanation:

Given

Vertices: (−1, 5), (4, 2), and (9, −4)

Cost per foot = $8

Required

Determine the cost of fencing (-1, 5) and (4, 2)

First, we need to determine the distance between (-1, 5) and (4, 2)

Distance, d is calculated as follows:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Where

(x_1,y_1) = (-1, 5)

(x_2,y_2) =(4, 2)

So, we have:

d = \sqrt{(4 - (-1))^2 + (2 - 5)^2}

d = \sqrt{(4 +1))^2 +  -3^2}

d = \sqrt{5^2 +  -3^2}

d = \sqrt{25 +  9}

d = \sqrt{34}

d = 5.83095189485

<em />d = 5.831<em> -- Approximated;</em>

If the cost of 1 foot is $8.

5.831 feet will cost:

Cost= 5.831 * \$8

Cost= \$46.648

<em />Cost= \$47<em> -- Approximated</em>

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A triangle has one leg that measures 14 feet and the hypotenuse is 50 feet. What is the length of the other leg?
Aliun [14]
Ok so we are using the Pythagorean theorem so were gonna do A^2 + B^2 = C^2

It don't say which leg we have so you can use either a or b.
Which would get us 14^2 + B^2 = 50^2
14*14 =196 , 50 *50 =2500
Then we have to  subtract the two.
So 2500 - 196 = 2,304
Then you take the take the square root of that answer and you have your other leg. 
The square root of 2,304 is 48
So the missing leg = 48
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4 years ago
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Step-by-step explanation:

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8 0
3 years ago
David made a triangle with sides 6 cm, 9cm , 12 cm. George wanted to make a triangle bigger in size but similar to that drawn by
SashulF [63]

Step-by-step explanation:

Given :

\triangle ABC \sim \triangle XYZ .△ABC∼△XYZ.

AB = 6\:cm, \:BC = 9 \:cm, CA = 12 \:cmAB=6cm,BC=9cm,CA=12cm

Let \: XY = 10\:cm, \:YZ = x \:cm, \: XZ = y /:cmLetXY=10cm,YZ=xcm,XZ=y/:cm

\frac{AB}{XY} = \frac{BC}{x} = \frac{CA}{y}XYAB=xBC=yCA

\blue {( The \: lengths \:of \: corresponding }(Thelengthsofcorresponding

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\implies \frac{6}{10} = \frac{9}{x} = \frac{12}{y}⟹106=x9=y12

i) \implies \frac{6}{10} = \frac{9}{x}i)⟹106=x9

\implies x = \frac{9 \times 10}{6}⟹x=69×10

\implies x = 15\:cm⟹x=15cm

ii) \implies \frac{6}{10} = \frac{12}{y}ii)⟹106=y12

\implies y = \frac{12 \times 10}{6}⟹y=612×10

\implies y = 20\:cm⟹y=20cm

Therefore.,

\red { Value \:of \:x } \green { = 15\:cm }Valueofx=15cm

\red { Value \:of \:y } \green { = 20\:cm }Valueofy=20cm

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3 years ago
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Answer:

B

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Step-by-step explanation:

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