The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= 
...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (
= k
k=
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<span>A) 5x + 7y = 3
B) 2x + 3y = 1
Multiplying Equation B by -2.5
</span><span>B) -5x -7.5y = -2.5 Then adding this to Equation A)
A) 5x + 7y = 3</span>
-.5y = .5
y = -1
Since
<span>2x + 3y = 1 then
2x -3 = 1
then x = 2
</span>
Answer:
EASY PEASY
Step-by-step explanation:
9²
HOPE IT HELPS YOU
Answer:
She runs 4 miles in one hour
Step-by-step explanation:
5 divided by 1.25=4
The answer to your problem is 6
