A line has a slope of and a run = 50. What is the rise? 25 50 100
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Answer:
Check it below
Step-by-step explanation:
Hello!
By definition, the intercept of the 3 bisectors, within a triangle is the Incenter. So let's get started, by tracing three bisectors.
In the triangle PQR::
- Use a compass, open its legs with a little more than half of
. Place the needle point in the vertex of P. Mark!
- Do the same, placing the needle point in Q, following
direction. Mark
- Repeat it with the other triangle's line segment, namely:
4.Trace with a ruler, from each intersection point a line. You'll trace three lines then.
5. Place the compass' needle point in this intersection point, (inside the triangle) with a hinge up to the triangle side, draw the circle inscribed.
Answer: at the values where cos(x) = 0
Justification:
1) tan(x) = sin(x) / cos(x).
2) functions have vertical asymptotes at x = a if Limit of the function x approaches a is + or - infinity.
3) the limit of tan(x) approaches +/- infinity where cos(x) approaches 0.
Therefore, the grpah of y = tan(x) has asymptotes where cos(x) = 0.
You can see the asympotes at x = +/- π/2 on the attached graph. Remember that cos(x) approaches 0 when x approaches +/- (n+1) π/2, for any n ∈ N, so there are infinite asymptotes.
Justification:
1) tan(x) = sin(x) / cos(x).
2) functions have vertical asymptotes at x = a if Limit of the function x approaches a is + or - infinity.
3) the limit of tan(x) approaches +/- infinity where cos(x) approaches 0.
Therefore, the grpah of y = tan(x) has asymptotes where cos(x) = 0.
You can see the asympotes at x = +/- π/2 on the attached graph. Remember that cos(x) approaches 0 when x approaches +/- (n+1) π/2, for any n ∈ N, so there are infinite asymptotes.