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erastova [34]
3 years ago
6

Three voltmeters are connected in parallel across the output of a voltage source:

Computers and Technology
1 answer:
amm18123 years ago
4 0

Answer:

12.18 Volts.

Explanation:

Since these voltmeters are connected in parallel.So the voltage across the parallel connection remains the same but all the three voltmeters are giving different reading this may be because of the different resistances in the wires connected to the voltmeters.

So the probable voltage is the mean of the readings.

probable voltage=[tex](12.23+12.1+12.2)/3[/tex]

=12.18 Volts.

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Your company has purchased another company that also uses Windows Server 2016 and Active Directory. Both companies need to be ab
Scorpion4ik [409]

Answer:

Create a two-way forest trust

Explanation:

The aim here is to ensure that both companies are able to access the forest resources of each other. The creation of a Two-way Forest Trust would guarantee that as if the Two-way Forest Trust is created between Forest A and Forest B, being the forest resources of the two companies respectively, then all the domains in Forest A will trust every domain in Forest B and vice versa.

5 0
3 years ago
How to create a comparator generic type in java.
KIM [24]

Answer:

public class Person {

//fields

private int id;

private String name;

private Payment pay;

//constructor

public Person(String name, int id,

int startSal, int startBon){

this.name = name;

this.id = id;

this.pay = new Payment(startSal, startBon);

}

//method get name

public String getName(){

return name;

}

//method get id

public int getId(){

return id;

}

//method get start salary

public int getStartSalary(){

return pay.startSalary;

}

//method get start bonus

public int getStartBonus(){

return pay.startBonus;

}

//inner payment class

private class Payment{

int startSalary;

int startBonus;

public Payment(int sal, int bon){

this.startSalary = sal;

this.startBonus = bon;

8 0
2 years ago
In c please
Paraphin [41]

Answer:

#include <stdio.h>

#include <ctype.h>

void printHistogram(int counters[]) {

   int largest = 0;

   int row,i;

   for (i = 0; i < 26; i++) {

       if (counters[i] > largest) {

           largest = counters[i];

       }

   }

   for (row = largest; row > 0; row--) {

       for (i = 0; i < 26; i++) {

           if (counters[i] >= row) {

               putchar(254);

           }

           else {

               putchar(32);

           }

           putchar(32);

       }

       putchar('\n');

   }

   for (i = 0; i < 26; i++) {

       putchar('a' + i);

       putchar(32);

   }

}

int main() {

   int counters[26] = { 0 };

   int i;

   char c;

   FILE* f;

   fopen_s(&f, "story.txt", "r");

   while (!feof(f)) {

       c = tolower(fgetc(f));

       if (c >= 'a' && c <= 'z') {

           counters[c-'a']++;

       }

   }

   for (i = 0; i < 26; i++) {

       printf("%c was used %d times.\n", 'a'+i, counters[i]);

   }

   printf("\nHere is a histogram:\n");

   printHistogram(counters);

}

5 0
2 years ago
Q10: You cannot rename a compressed folder.
user100 [1]
<h2>Answer:</h2><h2>Oh yes you can. </h2>

Click slowly twice the folder.

Right click and choose rename.

4 0
3 years ago
write a program, using python, to determine the mean, median, and standard deviation of a list of numbers. In addition, count th
Mekhanik [1.2K]

Answer:

The program to this question can be given as:

Program:

import math   #import packages

import sys

number =  [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6]  #define list  

n = len(number)   # taking length of list

print("Sample Data: ",number)  #print list

#find Mean

print("Mean is: ")  #message  

add = sum(number)  # addition of numbers.

mean = add / n  #add divide by total list number.

print(str(mean))  #print mean

number.sort()   #short list by using sort function

#find Median

print("Median is: ")

if n % 2 == 0:        #conditional statement.

   median1 = number[n//2]  

   median2 = number[n//2 - 1]  

   median = (median1 + median2)/2

else:  

   median = number[n//2]  

print(str(median)) #print median

#find Standard deviation.

print("Standard Deviation :")

def SD(number):  #define function SD

   if n <= 1:      #check condition

       return 0.0   #return value.

   mean,SD = average(number), 0.0  

   # find Standard deviation(SD).

   for j in number:

       SD =SD+(float(j)-mean)**2

       #calculate Standard deviation holing in variable SD  

       SD =math.sqrt((SD)/float(n-1))#using math sqrt function.

   return SD  #return value.

def average(av):         #define function average

   n,mean =len(av), 0.0  

   if n <= 1:

       return av[0]   #return value.

   # calculate average

   for I in av:

       mean +=float(i)

       mean /= float(n)

   return mean             #return value.

print(SD(number)) #print value

Output:

Sample Data:  [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6]

Mean is:  

5.235294117647059

Median is:  

6

Standard Deviation :

2.140859045465338

Explanation:

In the above python program first, we import packages to perform maths and other functions. Then we declare the list that is number in the list the elements are given in the question. Then we declare variable n in this variable we take the number of elements present in the list and print the list first. In the list, we perform three operations that can be given as:

Mean:  

In the mean operation firstly we define the variable add in this variable we add all elements of the list by using the math sum function then we divide the number by number of elements present in the list. and sore the value in the mean variable and print it.

Median:

In the median section firstly we sort the list by using the sort function. Then we use the conditional statements for calculating median. In the if block first we modules the number by 2 if it gives 0. it calculates first and second median the add-in median .else it will print that number.

Standard Deviation:

In the standard deviation part first, we define two functions that is SD() function and average().In the SD() function we pass the list as the parameter. In this function we use the conditional statement in the if block we call the average() function and use for loop for return all values. In the average() function we calculate the average of the all number and return value. At last, we print all values.

7 0
3 years ago
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