What are the first five common multiples of 9 and 10?

There are 150 new employees at a tech company in Southern California. 30 new employees are randomly assigned to each orientation

Lunna [17]

Answer:

Step-by-step explanation:

There are 150 new employees in the sample space. There are 30 new employees in each event. P(C)= 1/5, is the probability that you choose new employees that has been assigned to the orientation group C.

3 0

3 years ago

Brainliest and 30 points please help

kolbaska11 [484]

Answer:

22. Perimeter = 52 units

Area = 160 Square Units

23. Notation form : $2 \times 10^{5}$

Standard Form : 200000

Step-by-step explanation:

22.

The formula for perimeter is

P = 2 (length + Width )

= 2 ( 2x+3x+1)

= 2(5x+1)

The Formula for Area of a rectangle is

A= length x width

A= $2x \times (3x+1)$

A= $6x^2+2x$

Now we have to find the Perimeter and Area for x = 5

P = 2(5 x 5 +1)

P= 2(26)

P=52 units

A= 6 x 5 x 5 + 2 x 5

A= 150 + 10

A= 160 square units

23.

A. By using rule of exponents , we can determine that both the results will be same.

B.

Miriam's calculation

$\frac{2.8 \times 10^{9}}{1.4 \times 10^{4}}$

$\frac{2.8}{1.4} \times 10^{9-4}$

$2 \times 10^5$

Priya's calculation

$\frac{2.8 \times 10^{2}}{1.4 \times 10^{-3}}$

$\frac{2.8}{1.4} \times 10^{2-(-3)}$

$2 \times 10^5$

Standard notation

$2 \times 10^5 = 200000$

4 0

3 years ago

I need help finding x please?

enot [183]

$\large\mathfrak{{\pmb{\underline{\blue{To\:find}}{\blue{:}}}}}$

The value of $x$ .

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

$\longrightarrow{\green{x\:=\: 25° }}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

We know that,

$\sf\purple{Sum\:of\:angles\:on\:a\:straight\:line\:=\:180°}$

➪ 125° + $x$ + 30° = 180°

➪ $x$ + 155° = 180°

➪ $x$ = 180° - 155°

➪ $x$ = 25°

Therefore, the value of $x$ is 25°.

Now, the three angles of the triangle are 125°, 25° and 30°.

$\large\mathfrak{{\pmb{\underline{\pink{To\:verify}}{\pink{:}}}}}$

✒ 125° + 25° + 30° = 180°

✒ 180° = 180°

✒ L. H. S. = R. H. S.

$\boxed{Hence\:verified.}$

$\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{ヅ}}}}}$

3 0

3 years ago

Read 2 more answers

What is the largest x where f(x) is discontinuous show work

natulia [17]

Answer:

x = 3

Step-by-step explanation:

reverse foil the denominator and find the largest solution.

x-3(x+1)

3 is the largest solution

6 0

2 years ago

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

(c)43 times

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0

3 years ago