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Anton [14]
3 years ago
10

The area of a rectangular room is 120 square feet. The width is 10 feet. What is the length?

Mathematics
2 answers:
ryzh [129]3 years ago
8 0
The length is 12 square feet. We know the area, and we know the width. The way to find the length is take the area, and divide it by the width. So 120 divided by 10. The answer to that is 12, so 12 square feet is your answer.
~Deceptiøn
melisa1 [442]3 years ago
3 0
Answer: 12 feet 

area of a rectangle is L x W 
since you are looking for the lenght, you divide 120 from 10 
which gives you the answer of 12. 

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Liula [17]
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  • x is the horizontal axis.
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Here Allie mistook the x and y axis completely oppositely.

→ First should be the x axis and then the y axis, (x, y)

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2 years ago
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Answer:

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 200          

Step-by-step explanation:

Step  1  :

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Equation at the end of step  1  :

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Step  2  :

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Divide  ————  by  4

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8 0
3 years ago
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) The National Highway Traffic Safety Administration collects data on seat-belt use and publishes results in the document Occupa
asambeis [7]

Answer:

We conclude that there is a difference in seat belt use.

Step-by-step explanation:

We are given that of 1,000 drivers 16-24 years old, 79% said they buckle up, whereas 924 of 1,100 drivers 25-69 years old said they did.

<u><em>Let </em></u>p_1<u><em> = population proportion of drivers 16-24 years old who buckle up .</em></u>

<u><em /></u>p_2<u><em> = population proportion of drivers 25-69 years old who buckle up .</em></u>

So, Null Hypothesis, H_0 : p_1-p_2 = 0      {means that there is no significant difference in seat belt use}

Alternate Hypothesis, H_A : p_1-p_2\neq 0      {means that there is a difference in seat belt use}

The test statistics that would be used here <u>Two-sample z proportion statistics;</u>

                     T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of drivers 16-24 years old who buckle up = 79%

\hat p_2 = sample proportion of drivers 25-69 years old who buckle up = \frac{924}{1100} = 84%

n_1 = sample of 16-24 years old drivers = 1000

n_2 = sample of 25-69 years old drivers = 1100

So, <u><em>test statistics</em></u>  =  \frac{(0.79-0.84)-(0)}{\sqrt{\frac{0.79(1-0.79)}{1000}+\frac{0.84(1-0.84)}{1100} } }  

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The value of z test statistics is -2.946.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u><em>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</em></u><em> </em>

<em>Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that there is a difference in seat belt use.

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Answer:

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Use Elimination (x)

(-1) (14t + 25s) = (78) (-1)

-14t - 25s = -78

14t + 61s = 150

+ -14t - 25s = -78

--------------------------

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14t + 61(2) = 150

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nadya68 [22]
We know that GCF stands for Greatest Common Factor and hence we need to apply this in solving the given problem. The solution is shown below:
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304x+3
The answer for the factored expression is 304X + 3.

6 0
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