Answer:
4x^2 - 4x - 3
Step-by-step explanation:
f(x) = 2x - 1
g(x) = x^2 - 4
g(f(x)) = ?
[substitute the x of g(x) with f(x)]
g(x) = x^2 - 4
g(f(x)) = (2x - 1)^2 - 4
[solve]
[binomial * binomial = quadratic equation]
[use FOIL method (first, outer, inner, last)]
g(f(x)) = (2x - 1)(2x - 1) - 4
g(f(x)) = (2x*2x) + (-2x) + (-2x) + (1) - 4
[combine like terms]
g(f(x)) = 4x^2 - 2x - 2x + 1 - 4
g(f(x)) = 4x^2 - 4x - 3
See the photo attached. The boxed answer is the corrected answer
Answer:
see below
Step-by-step explanation:
Put -1 where x is in each expression and evaluate it.
__
You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...
(x +1)
Substituting x=-1 into this factor makes it be ...
(-1 +1) = 0
__
Evaluating the first expression, we have ...

This first expression is one you want to "check."
You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)
Answer:
Y = 50
Step-by-step explanation:
Solve for Y:
Y - 9 = 41
Add 9 to both sides:
Y + (9 - 9) = 9 + 41
9 - 9 = 0:
Y = 41 + 9
41 + 9 = 50:
Answer: Y = 50
From the looks of it, I believe it is either 120, 125, or 126. If you have options, let me know so I can take a closer look.