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Burka [1]
3 years ago
5

Gordon throws a baseball into the air. It rises, stops when it reaches its greatest height, and then falls back down to the grou

nd. At what point does kinetic energy convert to potential energy?a. when the baseball is rising
b. when the baseball is falling
c. just after the baseball hits the ground
d. while the baseball is stopped in the air
Physics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

A) When the baseball is rising

Explanation:

When an object like the baseball is thrown into the air, the kinetic energy  is gradually converted into potential energy. When the baseball rises to its maximum height, the kinetic energy becomes zero and the kinetic energy is fully converted into potential energy.

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Which property best makes radio waves safe for diagnosing illnesses through magnetic resonance imaging?
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Answer:

It is used in MRI because it does not damage cells

Radio waves are used for space research because they have very long wavelengths

Explanation:

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4 0
3 years ago
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When the ignition is first turned on a click noise is heard from under the hood of a vehicle equipped with ETC. Technician A say
Ierofanga [76]

Answer:

Technician A says that this is the normal operation of the ETC self -test is the correct answer.

Explanation:

An engine control unit (ECU), also widely referred to as an engine control module (ECM), is a type of electronic control device that controls an internal combustion engine with a series of actuators to ensure maximum engine performance.

It achieves so by reading values from a multitude of sensors within the engine bay, translating data using multidimensional feedback maps (the so-called lookup tables) and modifying the actuators.

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4 0
3 years ago
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andreev551 [17]

Answer:

v_avg = 37 km/h

Explanation:

To find the average velocity in the complete trajectory you use the following formula:

v_{avg}=\frac{v_1+v_2}{2}   ( 1 )

v1: velocity in the first part of the trajectory = 70 km/h

v2: velocity in the second part of the trajectory = ?

You calculate v2 by using the following equation for a motion with constant velocity:

v_2=\frac{2.0km}{30min}*\frac{60min}{1h}=4\frac{km}{h}

you replace the values of v1 and v2 in (1) and you obtain:

v_{avg}=\frac{70km/h+4km/h}{2}=37\frac{km}{h}

hence, the average velocity is 37 km/h

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2 years ago
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