Answer:
Juno scientific payload includes:
- A gravity/radio science system (Gravity Science)
- A six-wavelength microwave radiometer for atmospheric sounding and composition (MWR)
- A vector magnetometer (MAG)
- Plasma and energetic particle detectors (JADE and JEDI)
- A radio/plasma wave experiment (Waves)
- An ultraviolet imager/spectrometer (UVS)
- An infrared imager/spectrometer (JIRAM)
Explanation:
Each mission of NASA has a specific set of instruments that it uses to perform scientific experiments on the desired heavenly body. In case of Juno, the mission for Jupiter has a series of instruments that would study domains of gravitational forces, magnetic effect, particle detection, radiation detection, UV/IR imaging, and plasma experiments.
Answer:
5) Displacement = +3.125 m
Displacement is in the same direction as the force vector.
6) Force = -53.89 N
Force is in an opposite direction relative to the displacement.
Explanation:
5) We are given;
Force; F = 160 N.
Workdone; W = +500 J
Now, formula for workdone is;
W = Force × displacement
Thus, displacement = Work/force
Displacement = 500/160
Displacement = +3.125 m
Thus, displacement is in the same direction as the force vector.
6) We are given;
Displacement; d = 18 m.
Workdone; W = -970 J
Like in the first answer above,
Workdone = Force × Displacement
Thus;
Force = Workdone/Displacement
Force = -970/18
Force = -53.89 N
Since force is negative and displacement is positive, it means force is in an opposite direction relative to the displacement.
Answer:
75 N
Explanation:
In this problem, the position of the crate at time t is given by

The velocity of the crate vs time is given by the derivative of the position, so it is:

Similarly, the acceleration of the crate vs time is given by the derivative of the velocity, so it is:
[m/s^2]
According to Newton's second law of motion, the force acting on the crate is equal to the product between mass and acceleration, so:

where
m = 5.00 kg is the mass of the crate
At t = 4.10 s, the acceleration of the crate is

And therefore, the force on the crate is:

The tank has a volume of
, where
is its height and
is its radius.
At any point, the water filling the tank and the tank itself form a pair of similar triangles (see the attached picture) from which we obtain the following relationship:

The volume of water in the tank at any given time is

and can be expressed as a function of the water level alone:

Implicity differentiating both sides with respect to time
gives

We're told the water level rises at a rate of
at the time when the water level is
, so the net change in the volume of water
can be computed:

The net rate of change in volume is the difference between the rate at which water is pumped into the tank and the rate at which it is leaking out:

We're told the water is leaking out at a rate of
, so we find the rate at which it's being pumped in to be

