A. The acceleration during the slide is 6.86 m/s²
B. The time taken to slide until he stops is 1.2 s
<h3>How to determine the force of friction</h3>
- Mass (m) = 81.5 Kg
- Coefficient of friction (μ) = 0.7
- Acceleration due to gravity (g) = 9.8 m/s²
- Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 N
- Frictional force (F) =?
F = μN
F = 0.7 × 798.7
F = 559.09 N
<h3>A. How to determine the acceleration</h3>
- Mass (m) = 81.5 Kg
- Frictional force (F) = 559.09 N
- Acceleration (a) =?
a = F / m
a = 559.09 / 81.5
a = 6.86 m/s²
<h3>B. How to determine the time </h3>
- Initial velocity (u) = 8.23 m/s
- Final velocity (v) = 0 m/s
- Decceleration (a) = -6.86 m/s²
- Time (t) =?
a = (v – u) / t
t = (v – u) / a
t = (0 – 8.23) / -6.86
t = 1.2 s
Learn more about acceleration:
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Answer:
The amount of the sun energy that could be collected.
Explanation:
Some limitations are, the amount of the sun's energy that could be collected the radiation of sun is nearly fixed. The place where we can put the solar panels are also limited.
The circulation system for mammals is very complex
Given:
The magnitude of each charge is q1 = q2 = 1 C
The distance between them is r = 1 m
To find the force when distance is doubled.
Explanation:
The new distance is
![\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%5E%7B%5Cprime%7D%3D%5Ctext%7B%202r%7D%20%5C%5C%20%3D2%5Ctimes1%20%5C%5C%20%3D2%5Ctext%7B%20%7Dm%20%5Cend%7Bgathered%7D)
The force can be calculated by the formula
![F=k\frac{q1q2}{(r^{\prime})^2}](https://tex.z-dn.net/?f=F%3Dk%5Cfrac%7Bq1q2%7D%7B%28r%5E%7B%5Cprime%7D%29%5E2%7D)
Here, k is the constant whose value is
![k=9\times10^9\text{ N m}^2\text{ /C}^2](https://tex.z-dn.net/?f=k%3D9%5Ctimes10%5E9%5Ctext%7B%20N%20m%7D%5E2%5Ctext%7B%20%2FC%7D%5E2)
On substituting the values, the force will be
![\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20F%3D9%5Ctimes10%5E9%5Ctimes%5Cfrac%7B1%5Ctimes1%7D%7B%282%29%5E2%7D%20%5C%5C%20%3D2.25%5Ctimes10%5E9%5Ctext%7B%20N%7D%20%5Cend%7Bgathered%7D)
Answer:
Frequency of the light will be equal to ![6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=6.97%5Ctimes%2010%5E%7B1%7DHz)
Explanation:
We have given wavelength of the light ![\lambda =430nm=430\times 10^{-9}m](https://tex.z-dn.net/?f=%5Clambda%20%3D430nm%3D430%5Ctimes%2010%5E%7B-9%7Dm)
Velocity of light is equal to ![v=3\times 10^8m/sec](https://tex.z-dn.net/?f=v%3D3%5Ctimes%2010%5E8m%2Fsec)
We have to find the frequency of light
We know that velocity is equal to
, here
is wavelength and f is frequency of light
So frequency of light will be equal to ![f=\frac{v}{\lambda }=\frac{3\times 10^8}{430\times 10^{-9}}=6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv%7D%7B%5Clambda%20%7D%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B430%5Ctimes%2010%5E%7B-9%7D%7D%3D6.97%5Ctimes%2010%5E%7B1%7DHz)
So frequency of the light will be equal to ![6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=6.97%5Ctimes%2010%5E%7B1%7DHz)