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3 years ago

What are two ways air resistance can be increased?

1 answer:

7 0

The increase in speed leads to an increase in the amount of air resistance. Eventually, the force of air resistance becomes large enough to balances the force of gravity. At this instant in time, the net force is 0 Newton; the object will stop accelerating. The object is said to have reached a terminal velocity.

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A physical (beam) is used to measure?

Kisachek [45]

Answer:

mass of a object is the answer

6 0

2 years ago

Read 2 more answers

A projectile thrown from the ground reached a horizontal displacement of 50 [m] and a maximum height of 100 [m]. What are the ma

Semenov [28]

Answer:

$\theta=82.87^0$

u = 44.44 m/s

Explanation:

given,

horizontal displacement = 50 m

maximum height = 100 m

initial velocity (v₀) = ?

launching angle(θ) = ?

using formula

$R = \dfrac{u^2sin2\theta}{g}$ ........(1)

$h = \dfrac{u^2sin\theta}{2g}$ .........(2)

dividing equation (2)/(1)

$\dfrac{h}{R} = \dfrac{\dfrac{u^2sin\theta}{2g}}{\dfrac{u^2sin2\theta}{g}}$

$\dfrac{h}{R} =\dfrac{sin^2\theta}{2sin2\theta}$

$\dfrac{4h}{R} =tan \theta$

$\theta= tan{-1}{\dfrac{4\times 100}{50}}$

$\theta=82.87^0$

now using equation (2)

$100 = \dfrac{u^2sin82.87^0}{2\times 9.81}$

u = 44.44 m/s

5 0

2 years ago

If the mass of the products measured 120 g, what would be the mass of the reactants?

aksik [14]

According to law of conservation of mass, mass of reactant = mass of products

So answer is C

Hope it helps!

7 0

3 years ago

Read 2 more answers

A 0.0450-kg golf ball initially at rest is given a speed of 25.0 m/s when a club strikes. If the club and ball are in contact fo

LuckyWell [14K]

Answer:

Average force, F = 562.5 N

Explanation:

Mass of the golf ball, m = 0.045 kg

Initially, it is at rest, u = 0

Final speed of the ball, v = 25 m/s

The club and the ball are in contact for, $t=2\ ms=2\times 10^{-3}\ s$

We need to find the average force acting on the ball. It can be calculated using the formula as :

$F\times t=m(v-u)$

$F=m\dfrac{v-u}{t}$

$F=0.045\times \dfrac{25}{2\times 10^{-3}}$

F = 562.5 N

So, the average force acting on the ball is 562.5 N. Hence, this is the required solution.

5 0

3 years ago

Currently, the Sun is thought to be located in the galactic _____________ about ____________ the center of the galaxy.

Ede4ka [16]

Answer:

a. Disk, 28 thousand light-years from

Explanation:

Since, a galactic disc is a component of disc galaxies, for instance spiral galaxies and lenticular galaxies. It consists of a stellar component and a gaseous component.

Also, the Sun lies within the galactic disk or in other words it is thought to be located in the galactic disk,

The Sun is located about 26,000 light-years away from the centre of the galaxy.

∵ From the given options 28,000 is nearest to 26,000

Hence, the sun is about 28 thousand light-years from the centre of the galaxy.

i.e. OPTION 'a' would be correct.

8 0

3 years ago