It is a nuclear reaction, where the nucleus of an atom splits into smaller parts
Answer:
A)0.00022s b)40363.6N c) 0.025m/s
Explanation:
Mass = 24g = 0.024kg, distance though the target = thickness of the target = 25cm = 0.25m
Initial speed of the bullet = 1300m/s, final speed = 930m/s
Using equation of motion
Distance = 1/2(vf+vi)*t (time in seconds)
t = 0.25*2/(1300+930) = 0.00022s
B) force exerted on the body
F = ma = m* (vf-vi)/t = 0.024*(930-1300)/0.00022
F = -40363N, it is negative because the body decelerated during this motion
C) using law of conservation of momentum,
M1*U1+ M2*U2(M2and U1 are the mass and initial speed of the body) = M1V1+ M2V2
The target was at rest so initial speed U2 = 0
0.024*1300 + 360*0 = 0.024*930 + 360*V2
31.2 = 22.32+360*V2
31.2-22.33 = 360*V2
V2 = 8.88/360 = 0.025m/s
Answer:
9,800 watts
Explanation:
The first step is to calculate the force
F= mg
= 500 × 9.8
= 4,900 N
The next step is to calculate the work done
= 4,900 × 100
= 490,000 joules
Therefore the power can be calculated as follows
Power= work done /time
= 490,000/50
= 9,800 watts
Answer:
The mass is 16 [g]
Explanation:
We have to remember the formula that defines density, which mentions that the density is equal to mass divided by the volume.
![Density = mass / volume\\where:\\density = 2[\frac{g}{cm^{3} } ]\\Volume = 8 [cm^{3}]](https://tex.z-dn.net/?f=Density%20%3D%20mass%20%2F%20volume%5C%5Cwhere%3A%5C%5Cdensity%20%3D%202%5B%5Cfrac%7Bg%7D%7Bcm%5E%7B3%7D%20%7D%20%5D%5C%5CVolume%20%3D%208%20%5Bcm%5E%7B3%7D%5D)
Now we clear the mass:
![mass= density*volume\\mass = 2[\frac{g}{cm^{3} }]*8[cm^{3} ]\\mass = 16 [g]](https://tex.z-dn.net/?f=mass%3D%20density%2Avolume%5C%5Cmass%20%3D%202%5B%5Cfrac%7Bg%7D%7Bcm%5E%7B3%7D%20%7D%5D%2A8%5Bcm%5E%7B3%7D%20%5D%5C%5Cmass%20%3D%2016%20%5Bg%5D)
