1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MatroZZZ [7]
3 years ago
12

Anything that has volume or mass

Physics
1 answer:
irinina [24]3 years ago
8 0
Any object, except antimatter, :)

You might be interested in
Tres móviles, A, B y C, con las mismas características tienen los siguientes estados: A se encuentra inicialmente en reposo y ca
Morgarella [4.7K]

Answer:

La respuesta es sí, hay una fuerza que actúa sobre el móvil A y es la única fuerza ya que A cae libremente bajo la influencia de la fuerza.

Explanation:

Según la primera ley de movimiento de Newton, un cuerpo continuará en su estado de reposo o en un movimiento uniforme en línea recta a menos que actúen sobre él fuerzas impresas.

Dado que el móvil A cae libremente, desde su estado de reposo inicial, según la primera ley de movimiento de Newton, experimenta una fuerza que actúa sobre él para hacer que caiga y continúe en caída libre.

El móvil B se mueve con una velocidad constante, por lo tanto, de acuerdo con la primera ley de movimiento de Newton, no hay fuerzas impresas que actúen sobre él.

El móvil C está completamente en reposo en el suelo, por lo tanto, tampoco hay fuerzas que actúen sobre él.

La respuesta es sí, hay una fuerza actuando sobre el móvil A y es la única fuerza cuando A cae libremente bajo la influencia de la fuerza.

6 0
3 years ago
If a person is 6.25 m away from a 60.0 w speaker, what is the sound level they are hearing?
vodka [1.7K]

Answer:

110.87 dB

Explanation:

(I got it right on Acellus)

I= P/4(pi)r^2 = 60/4(pi)6.25^2

60/4(pi)6.25^2=0.12223

B=10log(I/Io)

B=10log(0.12223/1*10^-12) = 110.87 dB

111 in sigfigs

4 0
2 years ago
Read 2 more answers
A fireman standing on a 15 m high ladder operates a water hose with a round nozzle of diameter 2.02 inch. The lower end of the h
Nataly_w [17]

Answer:

v₁ = 1,606 10⁴ m / s

Explanation:

For this exercise we must use Bernoulli's equation, let's use index 1 for the nozzle on the stairs and index 2 the pump on the street

              P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² +ρ g y₂

             

The pressure when the water comes out is the atmospheric pressure

           P₁ = P_atm

The difference in height between the street and the nozzle on the stairs is

           y₂-y₁ = 15 m

Now let's use the continuity equation

             v₁ A₁ = v₂ A₁

The area of ​​a circle is

             A = π r² = π (d/2)²

            v₁ π d₁²/ 4 = v₂ π d₂²/ 4

            v₂ = v₁ d₁² / d₂²

Let's replace

           P₂-P_atm + ½ ρ [ (v₁ d₁² / d₂²)²- v₁² ] + ρ g (y2-y1) = 0

           P₂- P_Atm + ρ g (y₂-y₁) = ½ ρ v₁² [1- (d₁/d₂)⁴]

           v₁² [1- (d₁/d₂)⁴] = (P₂-P_atm) ρ / 2 + g (y₂-y₁) / 2

Let's reduce the magnitudes to the SI system

           d₂ = 3.37 in (2.54 10⁻² m / 1 in) = 8.56 10⁻² m

           d₁ = 2.02 in = 5.13 10⁻² m

Let's calculate

            v₁² [1- (5.13 / 8.56) 4] = 449.538 10³ 10³/2  -9.8 15/2

            v₁² [0.8710] = 2.2477 10⁸ - 73.5 = 2.2477 10⁸

            v₁ = √ 2.2477 10⁸ /0.8710

             v₁ = 1,606 10⁴ m / s

4 0
3 years ago
An engine does 10 J of work and exhausts 25 J of waste heat during each cycle.
noname [10]
The thermal efficiency is defined as follows

\eta = 1 - \frac{Q_{\text{out}}}{Q_\text{in}},

and the energy which is put into the system is

Q_{\text{in}} = W_\text{out} + Q_\text{out}.

In your case Q_\text{in} = 25 \text{ J},W_\text{out}=10 \text{ J}.

So Q_\text{out}=10 \text{ J} which gives an efficiency of

\eta = 1 - \frac{10 \text{ J}}{25 \text { J}} = 0.6 = 60 \%.





4 0
3 years ago
11. A student lifts a 25 kg mass a vertical distance of 1.6 m in a time of 2.0 seconds.
goldenfox [79]

Answer:

a) 245 N

b) 392 J

c) 196 W

Explanation:

a) Force needed to lift the 25 kg object is the same as the weight of the object:

Force= m * g = 25kg * 9.8 \frac{m}{s^2} = 245 N

b) Work is the force exerted times the distance moved:

Work = F * d = 245N * 1.6 m = 392 Joules = 392 J

c) The power exerted is the quotient of the work done over the amount of time it took to move the object:

4 0
3 years ago
Other questions:
  • Find the wavelength of the ultrasonic wave emitted by a bat if it has a frequency of 4.0 * 10^4 Hz.
    14·2 answers
  • A hot air balloon is flying above Grovenburg. To the left side of the balloon, the balloonist measure the angle of depression to
    8·1 answer
  • Displacement vectors of 4 km north, 2 km south, 5 km north, and 5 km south combine total displacement of
    12·2 answers
  • What is light energy
    10·1 answer
  • A rubber ball is dropped from a height of 8m. After strikingthe floor, the ball bounces to a height of 5m. a. If the ball had bo
    13·1 answer
  • The kinetic energy of a baseball is doubled by changing the speed of the baseball. By what factor has its speed changed? √ 2 v i
    14·1 answer
  • PLEASE HELP !!
    5·1 answer
  • HELP I'll MARK BRAINLY
    13·2 answers
  • You have 2 objects flying towards you. One of them is havier with lower velocity and the other one is lighter but has higher vel
    8·1 answer
  • A backyard swimming pool with a circular base of diameter 6.00m is filled to depth 1.50m. (b) Two persons with combined mass 150
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!