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fredd [130]
3 years ago
15

The earliest radio broadcasts on Earth were emitted about 100 years ago. Approximately where are these initial radio waves now?

(Radio waves are a type of radiation, so they travel at the speed of light)
Physics
1 answer:
Gala2k [10]3 years ago
3 0

Answer:

100 ly are d=9.454255\times10^{17}m

Explanation:

The speed of light is, by definition (we define this and derive a definition of distance from there nowadays), c=299792458m/s. We want to know, at this speed, how much distance the radio signals travel in 100 years. Since each year has 365 days (not a leap one though), each day has 24 hours, each hour has 60 minutes and each minute has 60 seconds, the number of seconds in a year will be (365)(24)(60)(60)=31536000, so the distance traveled by the waves in 100 years will be:

d=vt=(299792458m/s)(100)(31536000s)=9.454255\times10^{17}m, which, of course, are 100 light years.

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9. A 50 kg physics i student trudges from the 1st floor to the 3rd floor, going up a total height of 13 m.
SVETLANKA909090 [29]

Answer:

6370 J

Explanation:

By the law of energy conservation, the work done by the student would be the change in potential enegy from 1st floor to 3rd floor, or a change of 13 m

W = E_p = mgh

where m = 50kg is the mass of the student, g = 9.8 m/s2 is the gravitational constant and h = 13 m is the height difference

W = 50*9.8*13 = 6370 J

3 0
3 years ago
A car has a mass of 1000 kg and accelerates at 2 m/s2. What net force is exerted on the car?
prisoha [69]

Answer:

1000N

Explanation:

Based on force=mass*acceleration, if the acceleration is constant at 2 metres per second squared, 1,000kg*2m/s^2=2,000N of force.

If the acceleration steadily increases to 2m/s^2 in 20 seconds, take the average which is 1m/s^2 therefore force=1,000N

6 0
3 years ago
What is the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s?
Alik [6]
1/2mv^2

1/2x12x10^2=600J

The kinetic energy is 600J
3 0
3 years ago
Read 2 more answers
What is a target ceiling ?
zloy xaker [14]

Answer:

Target ceiling. the upper limit of your physical activity. Target fitness zone. Above the threshold of training and below the target ceiling.

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Explanation:

5 0
3 years ago
3) A bird flies toward a tree limb at a 45-degree angle to the ground along a path that is 50 m long landing on the limb. Determ
marin [14]

Answer:

35 m

Explanation:

Given :

The distance of the path from the ground to the tree limb = 50 m

The angle between the path of flight of the bird towards the tree limb and the ground = 45 degrees

Therefore we can determine the height above which the bird perched above the ground by using the rules of the trigonometric ratios as;

We know that ,

$\sin 45^\circ =\frac{\text{perpendicular}}{\text{hypothenus}}$

$\sin 45^\circ =\frac{\text{BC}}{\text{AC}}$

$0.7  =\frac{\text{BC}}{\text{50}}$

\text{BC }= 0.7 \times 50

       = 35

Therefore, the bird perched on the tree limb at a height of 35 m.

6 0
3 years ago
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