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3 years ago

14. Find the slope of a line parallel to 3y - 6x = 9. (Lesson 3-4)

1 answer:

4 0

$\bf 3y-6x=9\implies 3y=6x+9\implies y=\cfrac{6x+9}{3}\implies y = \cfrac{6x}{3}+\cfrac{9}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{2}x+3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

a parallel line to that one above, will have the same exact slope, since parallel lines have the same slope.

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In a triangle ABC, A= 29°, B=36° and b=15.8cm. Find a, using sine rule.

Nastasia [14]

A= (b sin A)/ sinB

a= (15.8 sin29)/ sin36

a= 13.03 cm

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3 years ago

What can you weave into your game in order to make it easier to pinpoint a particular audience?

Viktor [21]

Answer:

B. A secret cheat

Step-by-step explanation:

Correct me if i am wrong

6 0

3 years ago

I need help with this question. IT IS NOT MULTICHOICE. again, IT ISNT MULTICHOICE. (brainliest, 12 pts)

Rasek [7]

Answer:

Part A) The given enrollment numbers as a pair of points are (0,900) and (3,1,500)

Part B) The slope of the line is $m=200\ \frac{students}{year}$ (see the explanation)

Part C) $P=200t+900$

Part D) $P=2,500\ students$

Step-by-step explanation:

Part A) Write the given enrollment numbers as a pair of points in the form (t,P)

Let

t ----> the number of years since 2009 (independent variable or input value)

P ---->the high school's student enrollment (dependent variable or output value)

we know that

For t=0 (year 2009) ----> P=900 students

The first ordered pair is (0,900)

For t=2012-2009=3 years ----> P=1,500 students

The second ordered pair is (3,1,500)

therefore

The given enrollment numbers as a pair of points are (0,900) and (3,1,500)

Part B) Find the slope of the line passing though the pair of points

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

(0,900) and (3,1,500)

substitute the values

$m=\frac{1,500-900}{3-0}$

$m=\frac{600}{3}$

$m=200\ \frac{students}{year}$

That means that the high school's student enrollment increase at rate of 200 students by year since 2009

Part C) Write an equation that relates the high school's student enrollment, P, to the number of years since 2009, t

we know that

The equation of a line in slope intercept form is equal to

$P=mt+b$

where

m is the slope

b is the P-intercept

In this problem we have

$m=200$

$b=900$ ---> represent the initial value ( value of P when the value of t is equal to zero)

substitute

$P=200t+900$

Part D) Predict the high school's enrollment in 2017

For t=2017-2009=8 years

substitute the value of t in the linear equation

$P=200(8)+900$

$P=2,500\ students$

3 0

3 years ago

o quociente entre a soma de soma de dois numeros e um deles e igual a 3. O inverso do dobro da soma deles e igual a 1/6 quais sa

shepuryov [24]

For get the solution of this task, we must make the system of equations.First it: "The quotient between the sum of two numbers and one of them is equal to 3" Let's take two values: a and b.(a+b)/b=3 --- it's will be first equation in our system.
and "The inverse of double the sum of them and equal to 1/6"1/2(a+b)=1/6 it's will be second equation in our system.
Attention at parenthesis.
System(a+b)/b=31/2(a+b)=1/6
by the first equation:(a+b)/b=3a+b=3ba=2b --- we will use this equation for second equation in system
1/2(2b+b)=1/61/3b)=1/63b=6b=2 and a=2b, that's mean a=1.The answer is pair (1;2)

5 0

3 years ago

Would you please help me solve for x it should be a degrees but I’m not sure what it is

Leno4ka [110]

Answer:

x=15º

Step-by-step explanation:

A triangle's angles add up to 180º.

∠A=30º

∠C=180º-45º

∠B=xº

To find ∠B we have to first find ∠C.

Since ∠C does not have an angle, knowing that a straight line is 180º we can subtract it from 45º to find ∠C.

180-45=135

∠C=135º

Now add ∠A and ∠C.

30+135=165

Subtract the sum from 180º

180-165=x

x=15º

Hope this helps :)

6 0

3 years ago